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nevsk [136]
3 years ago
8

What is the distance between (2, 8) and (-7, 8)?

Mathematics
2 answers:
ankoles [38]3 years ago
5 0

Answer:

9

Step-by-step explanation:

The distance between (2,8) and (-7,8) is 9

love history [14]3 years ago
5 0

Answer:9

Step-by-step explanation:

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Step-by-step explanation:

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Read 2 more answers
How do I solve The sum of a number and 3 is subtracted from 10 the result is 5
meriva

State the given in the question

Given that the sum of a number and 3 is subtracted from, the result is 5

State what is to be found in the question

We are to find the number. In other to achieve this, we would follow the steps below:

Step 1: Represent the number with an unknown

Let x represent the number

Step 2: Interpret the given statement mathematically

If x is the number, then the sum of the number and 3 would be

x+3

Then the sum of a number and 3 subtracted from 10 would be

10-(x+3)

Finally, when the sum of a number and 3 subtracted from 10, the result is 5, would be

10-(x+3)=5

Step 3: Solve for x in the mathematical interpretation of the given statement

The value of x is as calculated as shown below:

\begin{gathered} 10-(x+3)=5 \\ \text{Open the bracket or the parenthesis} \\ 10-x-3=5 \\ \text{collect like terms} \\ 10-3-5=x \\ 7-5=x \\ 2=x \\ \text{Therefore:} \\ x=2 \end{gathered}

Hence, the number is 5

4 0
1 year ago
Monique's son just turned 2 years old and is 34 inches tall. Monique heard that the average boy will grow approximately 2 5/8 in
tatuchka [14]

Answer:

The equation representing how old Monique son is \mathbf{a = 2 + \dfrac{8}{21}(q-34)}

Step-by-step explanation:

From the given information:

A linear function can be used to represent the constant growth rate of Monique Son.

i.e.

q(t) = \hat q \times t + q_o

where;

q_o = initial height of Monique's son

\hat q = growth rate (in)

t = time

So, the average boy grows approximately 2 5/8 inches in a year.

i.e.

\hat q = 2 \dfrac{5}{8} \ in/yr

\hat q =  \dfrac{21}{8} \ in/yr

Then; from the equation q(t) = \hat q \times t + q_o

34 = \dfrac{21}{8} \times 0 + q_o

q_o = 34\  inches

The height of the son as a function of the age can now be expressed as:

q(t) = \dfrac{21}{8} \times t + 34

Then:

Making t the subject;

q - 34 = \dfrac{21}{8} \times t

t = \dfrac{8}{21}(q-34)

and the age of the son  i.e. ( a (in years)) is:

a = 2 + t

So;

\mathbf{a = 2 + \dfrac{8}{21}(q-34)}

SO;

if q (growth rate) = 50 inches tall

Then;

\mathbf{a = 2 + \dfrac{8}{21}(50-34)}

\mathbf{a = 2 + \dfrac{8}{21}(16)}

a = 2 + 6.095

a = 8.095 years

a ≅ 8 years

i.e.

Monique son will be 8 years at the time Monique is 50 inches tall.

8 0
3 years ago
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