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ss7ja [257]
3 years ago
14

A parabola can be drawn given a focus of (6,0) and a directrix of y = -6. Write the

Mathematics
2 answers:
VLD [36.1K]3 years ago
7 0

Answer:

Equation of the parabola: 12y+36=(x-6)^2 or y=\frac{x^2}{12} -x

Vertex form: y=\frac{1}{12} (x-6)^2-3

Intercept form: y=\frac{x}{12} (x-12)

Step-by-step explanation: hope this helps please give brainlieat!

seraphim [82]3 years ago
4 0

Answer: y=\frac{x}{12} (x-12) is the incerpet form of this parabola!

Step-by-step explanation: but the other user provided the both forms and the equation of paraobola so his is way better give him brainliest he deserves it more than me!

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Students in classes, displayed below, ate the same ratio of cheese pizza slices to pepperoni pizza slices.
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4 0
3 years ago
Solve the formula for v 1 v1 . Average acceleration of an object: a= v 1 − v 0/ t<br> pls help
ziro4ka [17]

In this question , we have the formula of acceleration given, which is

a = \frac{v_{1} - v_{0}}{t}

And we have to solve for v_{0}

First we need to get rid of denominator t from right side and for that, we multiply both sides by t, that is

at = v_{1} - v_{0}

Now to solve for v1 , we need to get rid of v0, and for that , we add v0 to both sides, that is

v_{1} = at + v_{0}

And that's the required answer.

3 0
3 years ago
What is the volume of the square pyramid with base edges 4 m and height 3 m?
kicyunya [14]

Answer:

Volume of the pyramid = 16m³ or 16 cubic meters.

Step-by-step explanation:

The equation for the volume of a pyramid is:

V=\frac{b*h}{3}

where b = area of base and h = height.

In this case, the base is a square with a side length of 4m.

Area of the square base = (4m)² = b = 16m²

h = 3m

Insert b and a into the volume of a pyramid equation.

V=\frac{3m*16m}{3}

= 16m³

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8 0
2 years ago
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Usimov [2.4K]
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3 0
2 years ago
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n200080 [17]

Answer:

1) Between 0 and 1 minute the rate of change is 25 ft./min

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Step-by-step explanation:

1) Between 0, and 1 feet, we have;

The rate of change = (Final height - Initial height)/(Final time - Initial time)

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Between 0 and 1 minute the rate of change = 25 ft./min

2) Between 1, and 2 feet, we have;

The rate of change = (40 - 40)/(2 - 1) = 0 ft/min

Between 1 and 2 minute the rate of change = 0 ft./min

3) Between 2, and 4 feet, we have;

The rate of change = (15 - 40)/(4 - 2) = -12.5 ft/min

Between 2 and 4 minute the rate of change = -12.5 ft./min

7 0
3 years ago
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