Question

A parabola can be drawn given a focus of (6,0) and a directrix of y = -6. Write the

Answer 1

Answer:

Equation of the parabola: $12y+36=(x-6)^2$ or $y=\frac{x^2}{12} -x$

Vertex form: $y=\frac{1}{12} (x-6)^2-3$

Intercept form: $y=\frac{x}{12} (x-12)$

Step-by-step explanation: hope this helps please give brainlieat!

Answer 2

Answer: $y=\frac{x}{12} (x-12)$ is the incerpet form of this parabola!

Step-by-step explanation: but the other user provided the both forms and the equation of paraobola so his is way better give him brainliest he deserves it more than me!