Answer:
The answer is D; 1.45 x 10^-4
<span>You are given O2 and C3H8, this is a combustion
reaction. The chemical reaction is C3H8 + 10O2 à 3CO2 + 4H2O. You are also given the molar mass
of O2 which is 32.00 g/mol and C3H8 which is 44.1 g/mol. You are required to
find the mass of O2 in grams. Since you have the reaction, oe mole of C3H8 is
required to completely react 10 moles of O2. So,</span>
0.025g C3H8(1 mol C3H8/44.1 g C3H8)(10 mol O2/1
mol C3H8)(32 g O2/1 mol O2) = <u>0.1802 g O2
</u>
<span> </span>
The answer is;
- Real gas particles have significant volume
- Real gas particles have more complex interactions than ideal gas particles
When using the ideal gas equation (PV= nRT)particular assumptions are made. That the molecules of the gas occupy negligible space and that the molecules only interact through elastic collision. However, the molecules of real gas have a finite volume and they interact also through intermolecular forces (such as in partially-charged molecules).
Answer:
The melting point range of a substance is the temperature range from which the first crystal starts to melt, to the temperature at which the last crystal finishes melting. An impure substance is a type of mixture, so melting points can be used to find out if a substance is pure or impure.
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Explanation: