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kozerog [31]
3 years ago
9

HELP!!

Chemistry
1 answer:
wlad13 [49]3 years ago
6 0

Answer:

207.24.

Explanation:

The mass numbers of the 4 isotopes are  82+ 122 = 204,  82 + 125 = 207,

82 + 124 = 206 and 208.

The approximate atomic mass  is worked out by adding the products of their relative abundances  and mass numbers:

0.014*204 + 0.221*207 + 0.241*206 + 0.524*208

= 207.24.

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The ideal gas heat capacity of nitrogen varies with temperature. It is given by:
hammer [34]

Answer:

A)  1059 J/mol

B)  17,920 J/mol

Explanation:

Given that:

Cp = 29.42 - (2.170*10^-3 ) T + (0.0582*10^-5 ) T2 + (1.305*10^-8 ) T3 – (0.823*10^-11) T4

R (constant) = 8.314

We know that:

C_p=C_v+R

We can determine C_v from above if we make C_v the subject of the formula as:

C_v=C_p-R

C_V = 29.42-(2.7*10^{-3})T+(5.82*10^{-7})T2-(1.305*10^{-8})T3-(8.23*10^{-12})T4-8.314

C_V = 21.106-(2.7*10^{-3})T+(5.82*10^{-7})T2-(1.305*10^{-8})T3-(8.23*10^{-12})T4

A).

The formula for calculating change in internal energy is given as:

dU=C_vdT

If we integrate above data into the equation; it implies that:

U2-U1=\int\limits^{500}_{450}(21.106-(2.7*10^{-3})T+(5.82*10^{-7})T2-(1.305*10^{-8})T3-(8.23*10^{-12})T4\,) du

U2-U1=\int\limits^{500}_{450}(21.106-(2.7*10^{-3})T/1+(5.82*10^{-7})T2/2-(1.305*10^{-8})T3/3-(8.23*10^{-12})T4/4\,)

U2-U1= 1059J/mol

Hence, the internal energy that must be added to nitrogen in order to increase its temperature from 450 to 500 K = 1059 J/mol.

B).

If we repeat part A for an initial temperature of 273 K and final temperature of 1073 K.

then T = 273 K & T2 = 1073 K

∴

U2-U1=\int\limits^{500}_{450}(21.106-(2.7*10^{-3})T/1+(5.82*10^{-7})T2/2-(1.305*10^{-8})T3/3-(8.23*10^{-12})T4/4\,)

U2-U1=\int\limits^{500}_{450}(21.106-(2.7*10^{-3})273/1+(5.82*10^{-7})1073/2-(1.305*10^{-8})T3/3-(8.23*10^{-12})T4/4\,)

U2-U1= 17,920 J/mol

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4 years ago
Match the term with its description.
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Which of the following best describes the role of the Supreme Court in protecting Americans' civil rights and liberties?
Citrus2011 [14]

Answer:

OB

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4570 distance in kilometers
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Determine whether each substance will sink or float in corn syrup, which has a density of 1.36 g/cm3. Write “sink” or “float” in
kondor19780726 [428]

Answer:

Here's what I get

Explanation:

A substance with ρ < 1.36 g/cm⁻³ will float on corn syrup.

A substance with ρ > 1.36 g/cm⁻³ will sink in corn syrup

\begin{array}{rrr}\textbf{Substance} & \mathbf{\rho/g\cdot \textbf{cm}^{-3}}& \textbf{Sink/Float}\\\text{Gasoline} & 0.75 & \text{Float}\\\text{Water} & 1.00 & \text{Float}\\\text{Corn syrup} & 1.36 & -\\\text{Honey} & 1.42 & \text{Sink}\\\text{Titanium} & 4.54 & \text{Sink}\\\end{array}

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