Answer is: total pressure is 108.96 mmHg.

p(n-hexane) = 151.4 mmHg; pressure of n-hexane.
p(n-heptane) = 45.62 mmHg.
χ(n-hexane) = 0.600; mole fraction.
χ(n-heptane) = 1 - 0.6 = 0.400.
Using Raoult's Law: <span>
p(total) = p(n-hexane) · χ(n-hexane) + p(n-heptane) · χ(n-heptane).
</span>p(total) = 151.4 mmHg · 0.6 + 45.32 mmHg · 0.4.
p(total) = 108.96 mmHg.

6 0

4 years ago

The number that identifies an atom is the same as the number of: *

seropon [69]

Explanation:

atomic number = proton

3 0

3 years ago

Balance the following reaction: Mg+ HCl → MgCl2 + H2

Softa [21]

Mg + 2HCl --> MgCl2 + H2

8 0

4 years ago

Read 2 more answers

At normal temperature and pressure, air has

damaskus [11]

The mass of air is 43.3 kg.

V = lwh = 3.63 m × 3.39 m × 2.97 m = 36.55 m³

V = 36.55 m³ × $(\frac{100 cm}{1 \text m})^{3}$ × $\frac{1 mL}{ 1 cm^{3}}$ = 3.655 × 10⁷ mL

Mass of air = 3.655 × 10⁷ mL × $\frac{0.001184 g}{1 mL}$ = 43 300 g = 43.3 kg

6 0

3 years ago