13m 16p
Add three to every number next as well as move up three letters.
For example:
1A is the starting point.
To get from 1A to 4D you add three.
1 + 3 = 4
A to get to D is three letters up.
A b c D
Same thing for 4D to get to 7G.
4 +3 = 7
D to get to G
D e f G
Your answer:
I'm not sure if you wanted me to find the letter of the equation or the actual next part. On your question you have just 13 up there, no letter so if youre trying to find the letter (13m) is your answer.
If you're trying to find the next equation to the puzzle (16p) is your answer.
Hope this helped!:)
Since the "leading" runner in a race would be found in the first position, because he or she is in the lead, it means they are first, then I suppose I would find the "leading coefficient" in the first place in a polynomial as well.
Answer:
The length of each rope is 9.93 feet (Approx).
Step-by-step explanation:
As given
Emma, Brandy, and Damian will cut a rope that is 29.8 feet long into 3 jump ropes.
Each of the three jump ropes will be the same length.
Thus


Therefore the length of the each rope is 9.93 feet (Approx).
Answer:
There’s no choice
Step-by-step explanation:
Answer:
The lower class boundary for the first class is 140.
Step-by-step explanation:
The variable of interest is the length of the fish from the North Atlantic. This variable is quantitative continuous.
These variables can assume an infinite number of values within its range of definition, so the data are classified in classes.
These classes are mutually exclusive, independent, exhaustive, the width of the classes should be the same.
The number of classes used is determined by the researcher, but it should not be too small or too large, and within the range of the variable. When you decide on the number of classes, you can determine their width by dividing the sample size by the number of classes. The next step after getting the class width is to determine the class intervals, starting with the least observation you add the calculated width to get each class-bound.
The interval opens with the lower class boundary and closes with the upper-class boundary.
In this example, the lower class boundary for the first class is 140.