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3 years ago

Hey answer this y2-x if y=7, x = - 7 the 2 is an exponent and show your work

1 answer:

3 0

Plug them in..
1. (7)^2-(-7) = (7)•(7)-(-7)
2. 49-(-7) = 49+7 (if you are subtracting a negative, change the sign to a plus and take out the negative)
3. Add, 56 is your answer

You might be interested in

-3x + 3y = 4 -x+ y = 3

Natalka [10]

Answer:

No solution

Step-by-step explanation:

-3x + 3y = 4

-x + y = 3

Solve the equation for x:

Move the variable to the right side and change its sign

-x + y = 3

-x = 3 - y

Change the signs on both sides of the equation

-x = 3 - y

x = -3 + y

Substitute the given value of x into the equation -3x + 3y = 4

-3x + 3y = 4

x = -3 + y

-3(-3+y)+3y=4

Solve the equation for y

-3(-3+y)+3y=4

y = 0

There is no solution for y.

And since there's no solution for y, the system has no solution.

6 0

2 years ago

Simplify 3^2 x 3^4 x 3^6 A3^10 B3^12 C3^48 D3^0

kvasek [131]

Answer:

$\boxed{\sf\: B)\:3^{12}}$

Step-by-step explanation:

$\sf 3^2\times \:3^4\times \:3^6$

Apply exponent rule:

$\hookrightarrow \boxed{\sf a^b\times \:a^c=a^{b+c}}$

$\sf 3^2\times \:3^4\times \:3^6$

$\sf 3^{2+4+6}$

Add the numbers:

$\sf 2+4+6=12$

$\sf \:3^{12}$

________________________________

7 0

1 year ago

Which equation is modeled below?

masha68 [24]

Answer:

your answer is b bud... your welcome....

Step-by-step explanation:

just took the test

5 0

2 years ago

How can we classify the following shapes ? Please choose correct answers that apply !!!!!!!!!!!! Will mark Brianliest !!!!!!!!!!

liq [111]

Answer:

Step-by-step explanation:

Cause a square has all equal sides

5 0

2 years ago

Find all the zeros for each function P(x)=x^4-4x^3-x^2+20x-20

ivanzaharov [21]

Answer:

The zeros of the given polynomial function are

2,2, $\pm\sqrt{5}$

Step-by-step explanation:

Given polynomial is $P(x)=x^4-4x^3-x^2+20x-20$

To find the zeros equate the given polynomial to zero

ie., P(x)=0

$P(x)=x^4-4x^3-x^2+20x-20=0$

By using synthetic division we can solve the polynomial:

2_| 1 -4 -1 20 -20

0 2 -4 -10 20

_____________________

1 -2 -5 10 |_0

Therefore x-2=0

x=2 is a zero of P(x)

Now we can write the cubic equation as below:

$x^3-2x^2-5x+10=0$

Again using synthetic division

2_| 1 -2 -5 10

0 2 0 -10

______________

1 0 -5 |_0

Therefore x-2=0

x=2 is also a zero of P(x).

Now we have $x^2+0x-5=0$

$x^2-5=0$

$x^2=5$

$x^=\pm\sqrt{5}$ is a zero of P(x)

Therefore the zeros are 2,2, $\pm\sqrt{5}$

8 0

3 years ago