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Katena32 [7]
3 years ago
13

Please help me I’m stuck.

Mathematics
1 answer:
Svetlanka [38]3 years ago
6 0

Answer:

Step-by-step explanation:

We will use the general area formula for finding the area of triangle when you are given information for SAS, which we have been.

A=\frac{1}{2}absinC , where a and b are the given side lengths and C is the included angle. You can ONLY use this when you have the info for SAS in a triangle. For us,

a = 17, b = 15 and C = 35 degrees.  Filling in:

A=\frac{1}{2}(17)(15)sin35

Do that on your calculator in degree mode and you'll find the area to be

73.1 meters squared

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Answer:

No; Because g'(0) ≠ g'(1), i.e. 0≠2, then this function is not differentiable for g:[0,1]→R

Step-by-step explanation:

Assuming:  the function is f(x)=x^{2} in [0,1]

And rewriting it for the sake of clarity:

Does there exist a differentiable function g : [0, 1] →R such that g'(x) = f(x) for all g(x)=x² ∈ [0, 1]? Justify your answer

1) A function is considered to be differentiable if, and only if  both derivatives (right and left ones) do exist and have the same value. In this case, for the Domain [0,1]:

g'(0)=g'(1)

2) Examining it, the Domain for this set is smaller than the Real Set, since it is [0,1]

The limit to the left

g(x)=x^{2}\\g'(x)=2x\\ g'(0)=2(0) \Rightarrow g'(0)=0

g(x)=x^{2}\\g'(x)=2x\\ g'(1)=2(1) \Rightarrow g'(1)=2

g'(x)=f(x) then g'(0)=f(0) and g'(1)=f(1)

3) Since g'(0) ≠ g'(1), i.e. 0≠2, then this function is not differentiable for g:[0,1]→R

Because this is the same as to calculate the limit from the left and right side, of g(x).

f'(c)=\lim_{x\rightarrow c}\left [\frac{f(b)-f(a)}{b-a} \right ]\\\\g'(0)=\lim_{x\rightarrow 0}\left [\frac{g(b)-g(a)}{b-a} \right ]\\\\g'(1)=\lim_{x\rightarrow 1}\left [\frac{g(b)-g(a)}{b-a} \right ]

This is what the Bilateral Theorem says:

\lim_{x\rightarrow c^{-}}f(x)=L\Leftrightarrow \lim_{x\rightarrow c^{+}}f(x)=L\:and\:\lim_{x\rightarrow c^{-}}f(x)=L

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Assignment: \bold{Factor \ 4u^2-28u+49}

<><><><><>

Answer: \boxed{\bold{\left(2u-7\right)^2}}

<><><><><>

Explanation: \downarrow\downarrow\downarrow

<><><><><>

[ Step One ] Rewrite \bold{4u^2-28u+49}

\bold{\left(2u\right)^2-2\cdot \:2u\cdot \:7+7^2}

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\bold{a=2u,\:b=7}

\bold{\left(2u-7\right)^2}

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\bold{\rightarrow Rhythm \ Bot \leftarrow}

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