The kids have to wait for 1 hour to get their bags.
<u>Step-by-step explanation:</u>
Given that,
A bus with kids and a truck with their bags started moving from the school to the camp at the same time.
- The speed of the bus was 60 mph.
- It took kids 3 hours to reach the camp.
<u>To find the distance traveled by the bus :</u>
⇒ Distance = Speed × Time
⇒ 60 × 3
⇒ 180 m
∴ The distance is 180 m.
<u>To find the time taken by the truck to reach the camp :</u>
- The speed of the truck was 45 mph.
- We found the distance as 180 m.
Time taken = distance / speed.
⇒ 180 / 45
⇒ 4 hours.
∴ The time taken by the truck to reach the camp is 4 hours.
<u>To find how long the kids have to wait for their bags :</u>
The time taken by the truck to reach the camp - the time it took for the kids to arrive.
⇒ 4 hours - 3 hours
⇒ 1 hour.
∴ The kids have to wait for 1 hour to get their bags.
Answer:
Step-by-step explanation:
we are given equation as
Since, we have to solve it by using complete square
so, firstly we will complete square
and then we can solve for x
step-1:
Factor 2 from both sides
step-2:
Simplify it
step-3:
Add both sides 3^2
now, we can complete square
step-4:
Take sqrt both sides
step-5:
Add both sides by 3
we get
Answer:
40 mph
Step-by-step explanation:
We assume "outbound" refers to the trip <em>to the lake</em>. The ratio of speeds is inversely proportional to the ratio of times, so ...
outbound speed : inbound speed = 4 : 3
These differ by one ratio unit, so that one ratio unit corresponds to the speed difference of 10 mph. Then the 4 ratio units of outbound speed will correspond to ...
4×10 mph = 40 mph
Paul's average speed on the outbound trip was 40 mph.
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The distance to the lake was 120 mi.
