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vladimir1956 [14]

2 years ago

15

Bruce has a bottle with 60% lemon juice and the rest water.

1 answer:

Dimas [21]2 years ago

3 0

The percent of water would be 40%

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Use the net to find the lateral area of the cylinder.

navik [9.2K]

Hi there!

The formula for the lateral area of a cylinder is LA = 2 x pi x r x h. Using this formula, we can plug in the given values and solve for the lateral area.

WORK:
LA = 2pi x r x h
LA = 2pi x 4.5 x 17
LA = 153pi mm^2

The correct answer is the first option - 153pi mm^2

Hope this helps!! :)
If there's anything else that I can help you with, please let me know!

7 0

2 years ago

(-3c+6) + (-c+8) simplify with a step by step please

mel-nik [20]

Step-by-step explanation:

$= ( - 3c + 6) + ( - c + 8)$

$= - 3c + 6 - c + 8$

$= - 3c - c + 6 + 8$

= -4c + 14

hence -4c + 14 is the answer ...

hope it helped !!

6 0

1 year ago

What is the scale factor when a larger image Q has an area of 36 square units and the smaller version has an area of 9 square un

schepotkina [342]

Answer:

6

Step-by-step explanation:

scale factor means the amount of times you need to multiply

so,

36/9

=6

5 0

2 years ago

You buy a car for $22,000 and every year your car depreciates by 14% (in other words, you car decreases in value by 14% every ye

Citrus2011 [14]

Answer:

The car worth in 4 years will be $9,880

4 0

2 years ago

A student solves the following equation and

Phoenix [80]

Answer:

Since the equation is undefined for -2

Therefore, NO SOLUTION for the given equation.

Step-by-step explanation:

Considering the expression

$\frac{3}{a+2}-6\cdot \frac{a}{-4+a^2}=\frac{1}{a-2}$

$\frac{3}{a+2}-\frac{6a}{-4+a^2}=\frac{1}{a-2}$

$\mathrm{Find\:Least\:Common\:Multiplier\:of\:}a+2,\:-4+a^2,\:a-2:\quad \left(a+2\right)\left(a-2\right)$

$\mathrm{Multiply\:by\:LCM=}\left(a+2\right)\left(a-2\right)$

$\frac{3}{a+2}\left(a+2\right)\left(a-2\right)-\frac{6a}{-4+a^2}\left(a+2\right)\left(a-2\right)=\frac{1}{a-2}\left(a+2\right)\left(a-2\right)$

as

$\frac{3}{a+2}\left(a+2\right)\left(a-2\right):\quad 3\left(a-2\right)$

$-\frac{6a}{-4+a^2}\left(a+2\right)\left(a-2\right):\quad -6a$

$\frac{1}{a-2}\left(a+2\right)\left(a-2\right):\quad a+2$

so equation becomes

$3\left(a-2\right)-6a=a+2$

$-3a-6=a+2$

$-3a-6+6=a+2+6$

$-4a=8$

$\mathrm{Divide\:both\:sides\:by\:}-4$

$\frac{-4a}{-4}=\frac{8}{-4}$

$a=-2$

$\mathrm{Verify\:Solutions}$

$\mathrm{Take\:the\:denominator\left(s\right)\:of\:}\frac{3}{a+2}-6\frac{a}{-4+a^2}-\frac{1}{a-2}\mathrm{\:and\:compare\:to\:zero}$

$\mathrm{Solve\:}\:a+2=0:\quad a=-2$

$\mathrm{Solve\:}\:-4+a^2=0:\quad a=2,\:a=-2$

$\mathrm{Solve\:}\:a-2=0:\quad a=2$

So the following points are undefined

$a=-2,\:a=2$

Since the equation is undefined for -2

Therefore, NO SOLUTION for the given equation.

4 0

2 years ago