Answer:
First, Juliana should write the function as an equation that equates to f(x). She can do this by translating each of the action phrases stated in the question into the form of an expression.
Take the equation f(x) and find its inverse. In the equation, change f(x) to the y variable and switch the x and y variable. Then, isolate y by moving all values to the other side of the equal sign in the backwards order of operations. The y variable should then be changed to f⁻¹(x).
In the inverse function, substitute x for twenty-four and solve. In the final answer, leave in decimal form, rounded down if needed.
Answer:
y ≈ 12.3
Step-by-step explanation:
Using the SOH CAH TOA identity to get the value of y as shown;
sin theta = opposite/hypotenuse
opposite = y
hypotenuse = 15cm
theta = 180-(35+90)
theta = 180-125
theta = 55 degrees
sin 55 = y/15
y = 15sin55
y = 12.287
y ≈ 12.3 (to the nearest tenth)
Answer:
![x = 2.5](https://tex.z-dn.net/?f=%20x%20%3D%202.5%20)
Step-by-step explanation:
Surface area of cylinder = 2πr(h + r)
Volume of cylinder = πr²h
Given that S.A = Volume of the cylinder, therefore, we have:
2πr(h + r) = πr²h
Radius (r) is given as 2.5 cm
height (h) = x cm
Input the values and solve for x
2πr(h + r) = πr²h
2πr(h + r) = πr(rh)
2(h + r) = rh (πr cancels πr)
![2(x + 2.5) = 2.5*x](https://tex.z-dn.net/?f=%202%28x%20%2B%202.5%29%20%3D%202.5%2Ax%20)
![2x + 5 = 2.5x](https://tex.z-dn.net/?f=%202x%20%2B%205%20%3D%202.5x%20)
Subtract 2x from both sides
![2x + 5 - 2x = 2.5x - 2x](https://tex.z-dn.net/?f=%202x%20%2B%205%20-%202x%20%3D%202.5x%20-%202x%20)
![5 = 0.5x](https://tex.z-dn.net/?f=%205%20%3D%200.5x%20)
Divide both sides by 0.5
![\frac{5}{0.5} = \frac{0.5x}{0.5}](https://tex.z-dn.net/?f=%20%5Cfrac%7B5%7D%7B0.5%7D%20%3D%20%5Cfrac%7B0.5x%7D%7B0.5%7D%20)
![2.5 = x](https://tex.z-dn.net/?f=%202.5%20%3D%20x%20)
![x = 2.5](https://tex.z-dn.net/?f=%20x%20%3D%202.5%20)
N - number of sample = 66
X = 44
P=0.54
q= 1-0.54
66 C 44 * 0.54^44 * (1-0.54)^(66-44)
The Answer Is 540 Feet.
Angle AB is 45% of 1,200, 1/2 of the full track.
Do 0.45x1,200=540.