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2 years ago

PLEASE HELP FOR ALGEBRA TEST write an equation that contains the coordinates (0,-1) and (3,7)

Mathematics

1 answer:

ELEN [110]2 years ago

3 0

Answer:

The answer is y=8/3x-1

Step-by-step explanation:

7-(-1)/3-0

=8/3

y-y=m(x-x¹)

y-7=8/3(x-3)

y-7=8/3x-8

+7 +7

y=8/3x-1

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Length width height equals to 62, what is the maximum volume

joja [24]

Assuming that the given shape is a cuboid,

volume=l×w×h

v=s³ (since cuboids have same length, they have same side length)

62=s³
∛62=s
s=3.957 ≈ 4 units

Hope I helped :)

4 0

3 years ago

Which of the following are coefficient

malfutka [58]

Answer:

2 and -3

Step-by-step explanation:

because a coefficient is a numerical or constant quantity placed before and multiplying the variable in an algebraic expression (e.g. 4 in 4x).

so in 2x-3y+5, 2 and -3 are the coefficients.

4 0

3 years ago

Please help and show work!!

Advocard [28]

1/3x + y = -2

-1/3x -1/3x

y = -1/3x-2

4 0

3 years ago

Consider writing onto a computer disk and then sending it through a certifier that counts the number of missing pulses. Suppose

Furkat [3]

Answer:

a) 0.164 = 16.4% probability that a disk has exactly one missing pulse

b) 0.017 = 1.7% probability that a disk has at least two missing pulses

c) 0.671 = 67.1% probability that neither contains a missing pulse

Step-by-step explanation:

To solve this question, we need to understand the Poisson distribution and the binomial distribution(for item c).

Poisson distribution:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}
$

In which

x is the number of sucesses

$
e = 2.71828$ is the Euler number

$\mu$ is the mean in the given interval.

Binomial distribution:

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

Poisson mean:

$\mu = 0.2$

a. What is the probability that a disk has exactly one missing pulse?

One disk, so Poisson.

This is P(X = 1).

$P(X = 1) = \frac{e^{-0.2}*0.2^{1}}{(1)!} = 0.164
$

0.164 = 16.4% probability that a disk has exactly one missing pulse

b. What is the probability that a disk has at least two missing pulses?

$P(X \geq 2) = 1 - P(X < 2)$

In which

$P(X < 2) = P(X = 0) + P(X = 1)$

In which

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}
$

$P(X = 0) = \frac{e^{-0.2}*0.2^{0}}{(0)!} = 0.819$

$P(X = 1) = \frac{e^{-0.2}*0.2^{1}}{(1)!} = 0.164
$

$P(X < 2) = P(X = 0) + P(X = 1) = 0.819 + 0.164 = 0.983$

$P(X \geq 2) = 1 - P(X < 2) = 1 - 0.983 = 0.017$

0.017 = 1.7% probability that a disk has at least two missing pulses

c. If two disks are independently selected, what is the probability that neither contains a missing pulse?

Two disks, so binomial with n = 2.

A disk has a 0.819 probability of containing no missing pulse, and a 1 - 0.819 = 0.181 probability of containing a missing pulse, so $p = 0.181$

We want to find P(X = 0).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{2,0}.(0.181)^{0}.(0.819)^{2} = 0.671$

0.671 = 67.1% probability that neither contains a missing pulse

8 0

3 years ago

What is -157/20 as a decimal

abruzzese [7]

$-\frac{157}{20}=-\frac{140+17}{20}=-\left(\frac{140}{20}+\frac{17}{20}\right)=-7\frac{17}{20}\\\\-7\frac{17}{20}\to\ divide\ 17\ by\ 20\to\boxed{-7\frac{17}{20}=-7.85}\\\\other\ way\\\\-7\frac{17}{20}=-7\frac{17\cdot5}{20\cdot5}=-7\frac{85}{100}=\boxed{-7.85}$

4 0

3 years ago