The first step is to convert the 55 kg of Fe₃O₄ to moles by using the molar mass, that is, 231.55 g/mol (55 kg = 55000 gms),
55000 gms × 1 mole / 231.55 gms = 237.53 moles of Fe₃O₄
For the decomposition of every 1 mole of Fe₃O₄, +1118 kJ of energy is needed. Therefore, the energy needed to decompose 237.53 moles will be:
237.53 moles of Fe₃O₄ × 1118 kJ / 1 mole = 265558 kJ
Thus, there is a need of 265558 kJ of energy to decompose 55 kg of Fe₃O₄.
<span>The argument for biomass in place of fossil fuels centers in terms of GHG emissions has to do with the net balance of CO2. As Mr. Del Padre alludes to, the Carbon Cycle for biomass is considerably shorter in time than fossil fuels. While fossil fuels are a form of carbon sequestration, the time scale is on millions of years. The time to harvest energy crops is on the order of months to years, such that the CO2 removed from the atmosphere by plants while growing is equal to the CO2 upon combustion (or other processing.) However, biomass is also less energy dense, requiring more biomass than say coal to produce the same amount of steam to drive a turbine. E85 ethanol is roughly 30% less efficient than gasoline to drive a FlexFuel car, so there are trade-offs. Of course, the method of utilization (combustion, co-firing, pyrolysis, liquefaction) has a large impact on the net GHG emissions, and so it's difficult to suggest a blanket difference across both process and biomass type. There is a large literature on Life Cycle Analyses for a variety of biomass sources and energy production scenarios, which is a good place to start.
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The Lewis structure for H₂CO is shown in the attached picture. The central atom is the carbon. However, I'm not sure which bond you're referring to. There can be two answers. The two C-H bonds are sp³ hybridized because it is a single bond. The C=O bond is sp² hybridized because it is a double bond.
Following reactions are involved in present reaction
1) A<span>g+(aq) + Li(s) → Ag(s) + Li+(aq) </span><span>− 384.4kJ
2) </span><span>2Fe(s) + 2Na+(aq) → Fe2+(aq) + 2Na(s) + 392.3kJ
</span>3) <span>2K(s) + 2H2O(l) → 2KOH(aq) +H2(g) −393.1kJ
In above reaction, reaction 1 and 3 has negative value of </span>δh∘f, while reaction 2 has posiyive value of <span>δh∘f. As per the sign convention positive sign indicates that heat is given out during the reaction, while negative sign indicates heat is to be supplied for reaction to occur. In alternative words, product formed in reaction 2 is stable as compared to reactant. Hence, it is thermodynamically favorable. </span>
Larger gases produces more spectral lines than the smaller gases because they have more orbitals in their atoms.
Hydrogen has only one orbital in which an electron orbits. At the excited state, that is, when the electron gains energy, the number of energy level it can transcend is very few. For larger elements, they have more orbitals and when excited, they can move from the ground state to other energy levels at which they produce various unique spectral lines.