<u>Given:</u>
Mass of the ball = 35.2 kg
Momentum = 218 kg m/s
<u>To determine:</u>
The velocity of the ball
<u>Explanation:</u>
Momentum (p) of an object is the product of its mass (m) and velocity (v)
p = m*v
v = p/m = 218 kg.ms-1/35.2 kg = 6.19 m/s
Ans: The velocity of the ball is 6.19 m/s
Answer:
So ²³⁵UF₆ effuses 1.0043 times faster than ²³⁸UF₆
Explanation:
The rate of effusion of two gases A and B can be expressed by <em>Graham's law</em>:
![\frac{EffusionRateA}{EffusionRateB}=\sqrt{\frac{M_{B}}{M_{A}} }](https://tex.z-dn.net/?f=%5Cfrac%7BEffusionRateA%7D%7BEffusionRateB%7D%3D%5Csqrt%7B%5Cfrac%7BM_%7BB%7D%7D%7BM_%7BA%7D%7D%20%7D)
Where M is the molar mass, and in this case A is ²³⁵UF₆ while B is ²³⁸UF₆.
So now we <u>calculate the molar mass of each mass</u>:
²³⁵UF₆ ⇒235 + 6*19 = 349 g/mol
²³⁸UF₆ ⇒238 + 6*19 = 352 g/mol
Putting the data in Graham's law:
= 1.0043
So ²³⁵UF₆ effuses 1.0043 times faster than ²³⁸UF₆.
13 Al:
<span>1s² ,2s² ,2p</span>⁶,<span> 3s² ,3p¹
Answer A
hope this helps!</span>
Explanation:
number of particles or atom = number of moles × Avogadro's number
number of atoms = 12.34 × 6.02 × 10^23
= 7.43 × 10^24 atoms
D. Because it shows the best definition of matter