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Vlad [161]
2 years ago
14

Most elements on the periodic table are

Chemistry
2 answers:
ivanzaharov [21]2 years ago
5 0

Answer:

Metals

Explanation:

hope this helps

Sergeeva-Olga [200]2 years ago
4 0

Answer:

most elements on the periodic table are metal i hope help you

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2 nitrogen atoms, 4 hydrogen atoms and 3 oxygen atoms
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There are 1000 meters in 1 Kilometer.

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7 0
3 years ago
State the definition of the partial molar Gibbs energy.
balu736 [363]

Explanation :

As we know that the Gibbs free energy is not only function of temperature and pressure but also amount of each substance in the system.

G=G(T,P,n_1,n_2)

where,

n_1\text{ and }n_2 is the amount of component 1 and 2 in the system.

Partial molar Gibbs free energy : The partial derivative of Gibbs free energy with respect to amount of component (i) of a mixture when other variable (T,P,n_j) are kept constant are known as partial molar Gibbs free energy of i^{th} component.

For a substance in a mixture, the chemical potential (\mu) is defined as the partial molar Gibbs free energy.

The expression will be:

\bar{G_i}=\mu_i=\frac{\partial G}{\partial n_i}_{(T,P,n_j)}

where,

T = temperature

P = pressure

n_i\text{ and }n_j is the amount of component 'i' and 'j' in the system.

4 0
2 years ago
The pKa of lactic acid is 3.9. A lactate buffer will be useful from pH values ________. The pKa of lactic acid is 3.9. A lactate
Vedmedyk [2.9K]

Answer:

Explanation:

The usefulness of a buffer is its ability to resist changes in pH when small quantities of base or acid are added to it. This ability is the consequence of having both the conjugate base and the weak acid present in solution which will consume the added base or acid.  

This capacity is lost if the ratio of the concentration of conjugate base to the concentration of weak acid differ by an order of magnitude. Since  buffers having ratios differing by more will have their pH driven by either the weak acid or its conjugate base .

From the Henderson-Hasselbach equation we have that

pH = pKa + log [A⁻]/[HA]

thus

0.1 ≤  [A⁻]/[HA] ≤ 10

Therefore the log of this range is -1 to 1, and the pH will have a useful range of within +/- 1 the pKa of the buffer.

Now we are equipped to answer our question:

pH range = 3.9 +/- 1 = 2.9 through 4.9

7 0
3 years ago
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