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2 years ago

A current of 0.15 A is passed through an aqueous solution of K2PtCl4. How long will it take to deposit 1.00 g Pt(s) (M = 195.1)?

Chemistry

1 answer:

koban [17]2 years ago

7 0

First calculate the electric charge used to deposit 1.0 g Pt

C = (1.0 g Pt) (1 mol Pt / 195.1 g Pt) ( 2 mol e / 1 mol Pt) ( 96485 C / 1 mol e)

C = 989.08 C

C = It

Where I is the current

T is the time

T = C / i

T = 989.08 C / 0.15 A

T = 6593.88 s

T = 1.83 hrs

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You weigh out 0.1183 g of a complex salt to analyze for the percentage of cyanide ion in your complex salt. After dissolving the

Stels [109]

Answer:

25.35%

Explanation:

Again let me restate the the equation of the reaction;

H2O (ℓ) + 2 MnO4 - (aq) + 3 CN- (aq) → 2 MnO2 (s) + 3 CNO- (aq) + 2 OH- (aq)

Amount of potassium permanganate reacted = 10.2/1000 * 0.08035 = 8.1957 * 10^-4 moles

If 2 moles of MnO4 - reacts with 3 moles of CN-

8.1957 * 10^-4 moles of MnO4 - reacts with 8.1957 * 10^-4 * 3/2

= 1.229 * 10^-3 moles of CN-

Mass of CN- reacted = 1.229 * 10^-3 moles of CN- * 26.02 g/mol

= 0.03 g

Hence, percentage of the cyanide = 0.03 g/0.1183 g * 100

= 25.35%

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2 years ago

Very urgent/easy chem question easy points

aev [14]

Sodium chloride is the answer

8 0

2 years ago

Read 2 more answers

Methanethiol, CH3SH, has a substantial dipole mement (1.52) even though carbon and sulfer have identical electronegativities. Ex

AleksAgata [21]

Answer:

The whole molecule is polar because Sulfur has lone pairs but Carbon doesn't. Lone pairs count more toward polarity, shifting dipole toward S.

Explanation:

Even though carbon and sulfur have identical values of electronegativities, the molecule, $CH_3SH$ is polar because of the presence of the lone pairs on the sulfur atom.

The C-S bond is not polar because the both the atoms have electronegatiivty. <u>But S has lone pairs which can attract the bond pairs of the bond between the S and H and thus acquires slightly negative charge and H acquires slightly positive charge.</u>

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2 years ago

Before you start an investigation, you see the Hazard symbol for Electrical Hazard. What safety steps should you follow when con

Fantom [35]

Explanation:

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The safety steps are :

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3. Follow the clean up procedure properly.

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2 years ago

How would I do this? A beaker contains 50.0 mL of 0.25 M aluminum nitrate solution. What is the minimum volume of 0.2 M sodium s

Serhud [2]

The minimum volume of 0.2M sodium sulfide that will precipitate out aluminum from 50.0 mL, 0.25 M aluminum nitrate would be 0.094 L or 94 mL

<h3>Stoichiometric calculation</h3>

From the equation of the reaction:

$2Al(NO_3)_3 + 3Na_2S ---> Al_2S_3 + 6NaNO_3$

Mole ratio of Na2S and Al(NO3)3 = 3:2

Mole of 50.0 mL, 0.25 M Al(NO3)3 = 50/1000 x 0.25

= 0.0125 mole

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= 0.0188 mole

Volume of 0.2M, 0.0188 mole Na2S = 0.0188/0.2

= 0.094 L or 94 mL

More on stoichiometric calculations can be found here: brainly.com/question/8062886

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1 year ago