The answer is TRUE because in that ecuation there are 6 atoms or moles of mercury in both sides and you also have the required moles of oxygen
Answer: 10% (v/v).
Explanation:
V - unit is litre
m/m - by mass concentration
m/v - unit of density
v/v - concentration by volume
A. 599 mg x 1g/1000mg x 1mole/174.24g = 0.003438 moles
<span>b. 0.003438 moles x 1000 mmoles/mole = 3.438 moles </span>
<span>c. 0.003438 moles/0.741 L = 0.0046 M </span>
<span>d. [K+] = 2 x 0.0046 = 0.0092 M because each mole K2 SO4 yields 2 moles K+ </span>
<span>e. [SO42-] = 0.0046 M </span>
<span>f. 599 mg/0.741 L = 808.4 mg/L = 808 ppm </span>
<span>g. 0.599g/741 ml x 100 ml = 0.08 g/100 ml = 0.08% w/v </span>
<span>h. pK+ = -log [K+] = -log 0.0092 = 2.04 </span>
<span>i. pSO42- = -log [SO42-] = -log 0.0046 = 2.34</span>
It depends on the strength of the nitric acid. With dilute acid magnesium nitrate and hydrogen gas is formed. The gas reacts violently with a naked flame.
With concentrated nitric acid a violent reaction occurs and lots of reddish brown fumes of nitrogen oxides (NO and NO2) are produced.
