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bixtya [17]
3 years ago
15

Archeologist discovered a silver crown in an ancient tomb and sent it for analysis. You placed the crown in a tub of water and f

ound it displaces 238.1 ml of water. If the mass of the crown is 2.50kg did the archeologist find a crown of Real silver? How can u be sure?
Chemistry
1 answer:
gulaghasi [49]3 years ago
8 0

Answer:

Explanation:

The density of pure lead is 10.49g/cm³

Given parameters:

Volume of water displaced by the crown = 238.1ml

Mass of crown = 2.50kg

Solution

We would simply find the density of the discovered crown and compare with that of the standardized density of lead.

Density is an intensive property of matter and it is the same for any form of matter. It is amount of substance per unit volume:

               Density = \frac{mass}{volume}

We need to convert the given parameters to standard unit,

                                 1ml = 1cm³

         Therefore, the volume of water displaced is 238.1cm³

Also,

                       1kg  = 1000g

                       2.5kg = 2500g

    mass of the crown is 2500g

 

Density = \frac{2500}{238.1} = 10.49g/cm³

The crown is made of silver because the density matches with that of pure silver.

                       

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Answer:

1.65 L

Explanation:

The equation for the reaction is given as:

                        A            +            B           ⇄        C

where;

numbers of moles = 0.386 mol C  (g)

Volume =  7.29 L

Molar concentration of C = \frac{0.386}{7.29}

= 0.053 M

                        A            +            B           ⇄        C

Initial               0                           0                      0.530    

Change          +x                          +x                       - x

Equilibrium      x                           x                      (0.0530 - x)

K = \frac{[C]}{[A][B]}

where

K is given as ; 78.2 atm-1.

So, we have:

78.2=\frac{[0.0530-x]}{[x][x]}

78.2= \frac{(0.0530-x)}{(x^2)}

78.2x^2= 0.0530-x

78.2x^2+x-0.0530=0  

Using quadratic formula;

\frac{-b+/-\sqrt{b^2-4ac} }{2a}

where; a = 78.2 ; b = 1 ; c= - 0.0530

= \frac{-b+\sqrt{b^2-4ac} }{2a}   or \frac{-b-\sqrt{b^2-4ac} }{2a}

= \frac{-(1)+\sqrt{(1)^2-4(78.2)(-0.0530)} }{2(78.2)}  or \frac{-(1)-\sqrt{(1)^2-4(78.2)(-0.0530)} }{2(78.2)}

= 0.0204  or -0.0332

Going by the positive value; we have:

x = 0.0204

[A] = 0.0204

[B] = 0.0204

[C] = 0.0530 - x

     = 0.0530 - 0.0204

     = 0.0326

Total number of moles at equilibrium = 0.0204 +  0.0204 + 0.0326

= 0.0734

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V = \frac{nRT}{P}

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n (number of moles) = 0.0734 mole

R (rate constant) = 0.0821 L-atm/mol-K

T = 273.15 K  (fixed constant temperature )

V (volume) = ???

V=\frac{(0.0734*0.0821*273.15)}{(1.00)}

V = 1.64604

V ≅ 1.65 L

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3 years ago
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