Answer:
72.0 mL of steam is formed.
Explanation:
The reaction is :
You can treat coefficient of compounds as amount of volume used.
Therefore for 4 mL of ammonia 5 mL of oxygen is used to form 4 mL of nitric oxide gas and 6 mL of steam.
For 1 mL of ammonia 
(=1.25) mL of oxygen is used to form 
(=1) mL of nitric oxide gas and 
(=1.5) mL of steam.
OR
Just transform the chemical equation by dividing the whole equation by 4 so that the coefficient of 
become one like this
We don't know which one will be completely exhausted and which one will be left so we have to consider two cases :
<em>1. </em><em>Assume ammonia to be completely exhausted</em>
For 50 mL of ammonia 
(= 62.5) mL of oxygen is needed. But we have just 60 mL of oxygen so this assumption is false.
2. <em>Assume oxygen to be completely exhausted</em>
For 60 mL of oxygen only 
(=48) mL of ammonia is needed. In this case we have sufficient amount of ammonia. So this case is true.
Now we know that during complete reaction 48 mL of ammonia and 60 mL of oxygen is used which will form (= 48) mL of nitic oxide gas and 
(= 72) mL of steam.
Therefore <em>72 mL of steam </em>is formed.
The answer that complete the sentence is "Arrhenius base".
The complete sentence is: A substance that increases the concentration of hydroxide ions in aqueous solution is an Arrhenius base.
Arrhenius' acid and base model says that an acid is a substance that contains hydrogen and ionizes in aqueous solution producing protons (H+) and a base is a substance that cointains hydroxide and release it in aqueous solution.
Answer:
The reactant/reagent that would be most atom economical is EtI (Ethy Iodide) and KOH (potassium oxide) as base
This is because the iodo group are weak base hence they have a good leaving character (i.e they are unstable on their own ) which would increase the rate of reaction and the strong base KOH give the most atom economical
Explanation:
I’m pretty sure it’s gravity man
Shale actually forms in the part of the rock cycle called compaction.
