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kvasek [131]
3 years ago
12

a line is graphed on the xy-plane. If the line has a positive slope and a negative y-intercept, which of the following points ca

nnot lie on the line
Mathematics
2 answers:
sdas [7]3 years ago
6 0
If the line has a positive slope and a negative y-intercept, then the <span>points cannot lie on the line where x is negative and y is positive. The points never lie at quadrant 1. Hope this answers the question. Have a nice day. Feel free to ask more questions.</span>
azamat3 years ago
6 0

Answer: The correct graph is graph C.

Step-by-step explanation: Locate -3 on the y-axis. From there go up one and to the right one since the slope is 1 or  1/ 1 .

Which of the lines graphed has a slope of 1 and a y-intercept of -3?

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A car travels from City A to City B at
Debora [2.8K]

Answer:

90? maybe... i'm not positive but i hope it helped

Step-by-step explanation:

3 0
3 years ago
Which linear function represents the line given by the point slope equation y + 7= 2/3(x+6)
Andrews [41]

Hello from MrBillDoesMath!

Answer:   f(x) =   (2/3)*x -3   -- which is not a provided answer..


Discussion:


We are given that y + 7 = (2/3) * (x + 6). Multiply out the right hand side:


y + 7 = (2/3) * x + (2/3) * 6 = (2/3) *x + 12/3

        =   (2/3)*x + 4


Subtract 7 from both sides:

y + 7 - 7 = (2/3)*x + 4 - 7

or

y =  (2/3)*x -3



Thank you,

MrB


y + 7= 2/3(x+6)

7 0
3 years ago
A parabola can be drawn given a focus of (5, -3) and a directrix of y=1. Write the equation of the parabola in any form.
Anna71 [15]

Answer:

(x²-10x+33)/(-8) = y

Step-by-step explanation:

The distance between any point on a parabola from both its focus and directrix are the same.

Let's say we have a point (x,y) on the parabola. We can then say that using the distance formula,

\sqrt{(x-5)^2+(y-(-3))^2}is the distance between (x,y) and the focus. Similarly, the distance between (x,y) and the directrix is |y-1| (I use absolute value here because distance is always positive). We can find this equation by taking the shortest distance from the point to the line. Because the closest point to the line will be the same x value as the point itself, the distance is simply the distance between the y value of the point and the y value of the directrix.

Equating the two equations given, we have

\sqrt{(x-5)^2+(y-(-3))^2} = |y-1|

square both sides to get

(x-5)²+(y+3)²=(y-1)²

expand the y components

(x-5)² + y²+6y+9 = y²-2y+1

subtract y²+6y+9 from both sides

(x-5)² = -8y - 8

expand the x components

x²-10x+25 = -8y - 8

add 8 to both sides to isolate the -8y

x²-10x+33 = -8y

divide both sides by -8 to isolate y

(x²-10x+33)/(-8) = y

6 0
2 years ago
Which number is eqyal to 13​
Ostrovityanka [42]
Answer:
XIII

Hope this helps
6 0
2 years ago
you invest $2800 in an account that pays an interest of 5.5%, compounded continuously. calculate the balance of your account aft
LuckyWell [14K]

Hi, hope this helps you. Have a good day. :)

Answer:

A = $5,417.42 (balance of the account)

I = $2,617.42

5 0
3 years ago
Read 2 more answers
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