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Nana76 [90]
2 years ago
7

Here a brainliest if you get it right

Mathematics
1 answer:
oksian1 [2.3K]2 years ago
3 0

Answer:

D.(2, 2)

Step-by-step explanation:

  • Staring point = (2, -4)
  • Since he moved 6 units up, so, there will be change in only y-coordinate of the starting point and x-coordinate will remain unchanged.
  • End point of the segment = (2, - 4 + 6) = (2, 2)
You might be interested in
The base of a triangle is 4 meters shorter than the height. What are the height and length of the triangle if its area is 48 squ
Sergeeva-Olga [200]

Answer: H=12 and B=8

Looking at the problem, you are given the area, <em>a</em> , and told the h is 4 meters longer than <em>b; </em>in other words, <em>h</em>=<em>b</em>+4.

Since <em>a=</em>1/2<em>bh</em>, you can replace <em>a</em> with 48. Also, since <em>h</em> is <em>b</em>+4, you can replace that as well. You'd end up with this equation:

48=1/2b(b+4)

1. Seeing that 48 is 1/2 of <em>b,</em> you know that you have twice the value of 48, or 96. So, you can put that 96=<em>b(b+4). </em>

2.<em> </em>Now, thinking through factors of 96-  1 x 96, 2 x 48, 3 x 32, 4 x 24, 6 x 16, or 8 x 12, the only pair in which <em>h </em>is b+4 is 12 x 8.

Hope this helps,

Lacia :))

8 0
3 years ago
The sum of 3x and 1 is greater than-5 and less than or equal to 10
ira [324]

Answer:

x is greater than -2 and less than or equal to 3

Step-by-step explanation:

so the 3x + 1 is greater than -5

so 3x is greater than -6

we divide both sides by 3

then we find out that x is greater than -2

we also know that 3x + 1 is less than or equal to 10

so 3x is less than or equal to 9

we divide both sides by 3

then we find out that x is less or equal to 3

so we can say that x is greater than -2 and less than or equal to 3

4 0
2 years ago
Solve the differential equations dy/dx=((xy^2)+x)/y
arsen [322]

\displaystyle \dfrac{dy}{dx}=\dfrac{xy^2+x}{y}\\ \dfrac{dy}{dx}=\dfrac{x(y^2+1)}{y}\\ \dfrac{y}{y^2+1}\, dy=x\, dx\\ \int \dfrac{y}{y^2+1}\, dy=\int x\, dx\\ \dfrac{\ln (y^2+1)}{2}=\dfrac{x^2}{2}+C\\ \ln(y^2+1)=x^2+C\\ y^2+1=e^{x^2+C}\\ y^2=e^{x^2+C}-1\\ y=\sqrt{e^{x^2+C}-1} \vee y=-\sqrt{e^{x^2+C}-1}\\ \boxed{y=\sqrt{Ce^{x^2}-1} \vee y=-\sqrt{Ce^{x^2}-1}}\\

7 0
3 years ago
The graph of y = f(x) is shown below. What are all of the real solutions of f(x) = 0?
jasenka [17]

Answer:

-8 and -2

Step-by-step explanation:

f(x) basically means y and at the y value 0 the x values are -8 and -2 (also known as the roots of the function)

5 0
3 years ago
The graph of the function f(x) is shown below.
faust18 [17]
Remember, parenthaees are like < and > and brackets ar like ≤ and ≥

domain is how far the x values go
x is left to right

we see they go from -3 to 5, with a filled in dot at -3 and empty dot at 5
means include -3 but not including 5
so like -3≤x<5
or in interval notation
[-3,5) is the domain



range
highest to lowest y value

range is from y=3 to y=-1
we gots full dots so we use brackets
range is [-1,3]



Domain=[-3,5)
Range=[-1,3]


B. read above and understand it
5 0
3 years ago
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