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Katen [24]
3 years ago
12

Please Do 3 for 5 points.

Mathematics
1 answer:
alukav5142 [94]3 years ago
7 0

Answer:

44, 46, and 48

Step-by-step explanation:

add them and you should get 138.

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Evaluate cos(sin^-1(4/5)
PSYCHO15rus [73]

Step-by-step explanation:

Let \:   \: \theta =  \sin^{ - 1}  (\frac{4}{5})  \\  \\  \therefore \:  \sin\theta = \frac{4}{5} \\  \\  \because \:  { \cos}^{2} \theta =1  - { \sin}^{2} \theta  \\  \\  \therefore \: { \cos}^{2} \theta  = 1 - (\frac{4}{5} )^{2}  \\ \\   = 1 -  \frac{16}{25}  \\  \\  =  \frac{25 - 16}{25}  \\  \\  =  \frac{9}{25}  \\  \\   \therefore \:{ \cos}\theta  = \pm \:  \frac{3}{5}  \\  \\  \because \:  \theta \: lie \: in \: the \: first \: quadrant \\  \\  \therefore \: { \cos}\theta  =  \:  \frac{3}{5}  \\ \\  \implies \theta =  { \cos}^{ -1 }  \: \frac{3}{5}\\\\\implies \theta =  { \cos}^{ -1 }  \: \frac{3}{5}= { \sin}^{ -1 }  \: \frac{4}{5} \\  \\  \therefore \:  \cos( \ {sin}^{ - 1}  \frac{4}{5} ) \\ \\ =  \cos( \ {cos}^{ - 1}  \frac{3}{5} )   \\\\ = \frac{3}{5}  \\  \\   \purple{ \boxed{\therefore \: \cos( \ {sin}^{ - 1}  \frac{4}{5} ) = \frac{3}{5}}}

8 0
3 years ago
Find the compound Interest for Rs.18,800 ,calculated for 2 years at 13% rate of Interest compounded annually
Vinvika [58]

For compound interest, the formula is given below:

Amount = P(1+\frac{r}{100} )^{n}

Here, P = 18,800

n = 2

r = 13/100

So, Amount = 18,800(1+\frac{13}{100} )^{2}

18,800(1.13)^{2}

= 18,800 × 1.2769

= 24005.72

Compound Interest = Amount - Principal

Compound Interest = 24005.72 - 18800

= 5205.72

Hence, the compound interest for Rs.18,800, calculated for 2 years at 13% rate of interest compounded annually is Rs.5205.72.


4 0
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