Evaluate 36 divided by 8325

Mathematics

2 answers:

alexira [117]4 years ago

6 0

36÷6325=.0043243243

Hope this helps!

Tamiku [17]4 years ago

6 0

<span> the answer would be 36÷6325=.0043243243</span>

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The histogram represents the number of gallons of gasoline that drivers purchase weekly. Which bar represents the number of gall

padilas [110]

Answer:

option B) Bar 2

Step-by-step explanation:

The histogram represent the number of gallons of gasoline on x axis.

The number of drivers purchase weekly on y axis.

In this histogram 5 Bars are shown.

First bar represents = 5 drivers

Second bar represents = 6 drivers

Third bar represents = 1 driver

Fourth bar represents = 3 drivers

Fifth bar represents = = 4 drivers

So the second bar represents the the number of gallons most drivers purchased during the week.

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3 years ago

Given two parallel lines, same side interior angles are supplementary. Fill

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Vertical angles are equal
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2 years ago

This table shows the value, v, of a car based on its age, a, assuming normal usage.

Lorico [155]

Answer:

a. U(a) = 20000·0.9^a

b. about -$957 dollars per year

c. 13 years

Step-by-step explanation:

a) The age values are sequential, but the differences between "v" values are not constant. We suspect an exponential function. When we examine the ratios of adjacent table values, we find they are all 0.9, so the exponential function will be ...

U = (initial value)·(0.9^(age))

U(a) = 20000·0.9^a

b) The average rate of change for the one year between age 7 and age 8 will be U(8) -U(7). A calculator evaluates that difference as -$956.59, about -$957.

c) The car value drops by almost half in 6 years, so will drop by almost half of that in another 6 years. The car's age will be 12 or 13 years. A graph shows the age to be just over 13 years when the value is predicted to be $5000.

_____

A graphing calculator was used to evaluate the function and find the time associated with the given value. (See attached.) This is the "work" that was done to answer the questions.

The time to decrease to 1/4 of the original value can be found by solving ...

5000 = 25000·0.9^a

The solution is ...

a = log(.25)/log(0.9) ≈ 13.158 . . . . as found on the graph