Answer: an = a1 + d(n-1) or an = 24 + 6(n-1)
Step-by-step explanation:
Using the z-distribution, it is found that the 95% confidence interval for the proportion of all seafood sold in the United States that is mislabeled or misidentified is (0.3036, 0.3564).
<h3>z-distribution interval:</h3>
In a sample with a number n of people surveyed with a probability of a success of 
, and a confidence level of 
, we have the following confidence interval of proportions.
- In which z is the z-score that has a p-value of
.
For this problem:
- 1215 samples, hence
.
- 33% was mislabeled or misidentified, hence
.
- 95% confidence level, hence
, z is the value of Z that has a p-value of 
, so 
.
<h3>The lower limit of this interval is:</h3>
<h3>The upper limit of this interval is:</h3>
The 95% confidence interval for the proportion of all seafood sold in the United States that is mislabeled or misidentified is (0.3036, 0.3564).
You can learn more about the use of the z-distribution to build a confidence interval at brainly.com/question/25730047
Answer:
(6, -2)
Step-by-step explanation:
The midpoint of the segment RS is point M (5, 3). Therefore, the average of the x coordinates of R and S is 5, and the average of the y coordinates of R and S is 3. The x coordinate of R is 4. For 4 and the x coordinate of S to have an average of 5, the x coordinate of S must be 6. Therefore, our point is of the form (6, y). For 8 and the y coordinate of S to have an average of 3, the y coordinate of S must be -2. Therefore, our answer is (6, -2)
7n-22 ≥ 64
1. Move constant to the right.
7n ≥ 64 + 22
2. Combine like terms.
7n ≥ 86
3. Divide 7n by 7 to get n alone.
n ≥ 86
4. Divide 86 by 7.
n ≥ 86 / 7 OR n ≥ 12.29
So basically you must first use the step that got you here
