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2 years ago

I NEED THIS IN 12 MINUTES what is on flvs module 3 dba for preabgabra

Mathematics

1 answer:

GarryVolchara [31]2 years ago

7 0

Answer:

Greatest Common Factor: integer or variable multiplied by other integers or variables that creat a resultin product. factor x factor = product

difference of squares binomial: an expression where two perfect square terms are being subtracteda² - b² = (a+b)(a-b)quadratic: from "quad" meaning square, because the variable gets squared (like x2).

discriminant: tells you about the roots of a quadratic

general form: y = a(x - h)^2 + kstandard form: ax^2 + bx + c = 0root: a solution of an equation

zero: a value that gives you 0 for a function

x-intercept: where the graph crosses the x-axis

y-intercept: where the graph crosses the y-axis

extraneous: a solution that does not work

parabola: the graph of a quadratic

vertex: the turning point of the parabola

axis: line of reflection

translation: movement up/down and left/right of any parabola from standard position (f(x) = x2)

The basics of what you should know

Step-by-step explanation:

Can get brainiest pls

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Mario made a table with the rules below

Lady_Fox [76]

It will be option A.
x - coordinate is 1. If we multiply 3 with 1, it will be 3. And if we multiply 3 with 3, it will be 9.
y- coordinate is 1. If we add 3 with 1, it will be 4. And adding 3 with 4, we get 7.

Answer:

a- (1,1) (3,4) (9,7)

Hope you could get an idea from here.

Doubt clarification - use comment section.

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2 years ago

The points (3, 9) and (–3, –9) are plotted on the coordinate plane using the equation y = a • x.

marysya [2.9K]

The answer would be a=3

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2 years ago

The function y = x 2 - 10x + 31 has a ____

katrin [286]

Answer:

Option B. minimum is correct for the first blank

Option C. 6 is correct for second blank.

Step-by-step explanation:

In order to find the maxima or minima of a function, we have to take the first derivative and then put it equal to zero to find the critical values.

Given function is:

$f(x) = x^2-10x+31$

Taking first derivative

$f'(x) = 2x-10$

Now the first derivative has to be put equal to zero to find the critical value

$2x-10 = 0\\2x = 10\\x = \frac{10}{2} = 5$

The function has only one critical value which is 5.

Taking 2nd derivative

$f''(x) =2$

$f''(5) = 2$

As the value of 2nd derivative is positive for the critical value 5, this means that the function has a minimum value at x = 5

The value can be found out by putting x=5 in the function

$f(5) = (5)^2-10(5)+31\\=25-50+31\\=6$

Hence,

The function y = x 2 - 10x + 31 has a minimum value of 6

Hence,

Option B. minimum is correct for the first blank

Option C. 6 is correct for second blank.

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3 years ago

Is 1/3+ 5 perpendicular

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Answer:

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3 years ago

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A number divided by eleven.

Sliva [168]

Answer:

Take the alternating sum of the digits in the number, read from left to right. If that is divisible by 11, so is the original number. So, for instance, 2728 has alternating sum of digits 2 – 7 + 2 – 8 = -11. Since -11 is divisible by 11, so is 2728.

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3 years ago