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Vitek1552 [10]
3 years ago
7

Surface area please !!! will give brainliest to most accurate !

Mathematics
1 answer:
Natali5045456 [20]3 years ago
5 0
Is it 54?? im learning this right now literally lol so i did 12x9 divided by 2 because its a triangle
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How to simplify please help
Luda [366]

Okay, the image is a little tough to see, but I believe it looks something like this:

(5² -10 / 17 - 3 * 4) -1

The first step [remember PEMDAS] is parentheses

Next comes Exponents:

(25 - 10 / 17 - 3 * 4) -1

Then Multiplication:

(25 - 10 / 17 - 12) - 1

Then Division [which we can't do yet since it isn't fully simplified], so we skip to Addition... nothing again, then subtraction.

(15 / 5) - 1

Then we can divide:

(3) - 1

Then subtract!

2

The answer to your problem is 2.

Hope that helps!

4 0
4 years ago
How do you solve this y= 6x - 3 y= -3 i need to graph so if you can show how to graph it also
nalin [4]

Answer:

:)

Step-by-step explanation:

y=6x-3

y=-3

-3=6x-3

-3=6x-3

+3     +3

=6x

3 0
4 years ago
Read 2 more answers
Parth created a Box-and-Whisker Plot to show the average weight of the fish he caught over the weekend. What information does th
german
B. beacuse the middle wieght of the fish
6 0
3 years ago
When asked about favorite Thanksgiving leftovers, 5% of the people said turkey and 7/100 said mashed potatoes. Which food was mo
Serjik [45]

Answer: Mash Potatoes

Step-by-step explanation: 7/100 written as a percentages is 7%

5 0
2 years ago
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Prove that the triangle EDF is isosceles. Give reasons for your answer.
Gekata [30.6K]

Answer:

\triangle EDF is isosceles.

Step-by-step explanation:

Please have a look at the attached figure.

We are <u>given</u> the following things:

\angle EDF = y

\text{External }\angle DFG = 90 +\dfrac{y}{2}

Let us try to find out \angle E and \angle DFE. After that we will compare them.

<u>Finding </u>\angle DFE<u>:</u>

Side EG is a straight line so \angle GFE = 180

\angle GFE is sum of internal \angle DFE and external \angle DFG

\angle GFE = 180 = \angle DFE  + \angle DFG\\\Rightarrow 180 = \angle DFE + (90+\dfrac{y}{2})\\\Rightarrow \angle DFE = 180 - 90 - \dfrac{y}{2}\\\Rightarrow \angle DFE = 90 - \dfrac{y}{2} ....... (1)

<u>Finding </u>\angle E<u>:</u>

<u>Property of external angle:</u> External angle in a triangle is equal to the sum of two opposite internal angles of a triangle.

i.e. external \angle DFG = \angle E + \angle EDF

\Rightarrow 90+\dfrac{y}{2} = \angle E + y\\\Rightarrow \angle E = 90+\dfrac{y}{2}  -y\\\Rightarrow \angle E = 90-\dfrac{y}{2} ....... (2)

Comparing equations (1) and (2):

It can be clearly seen that:

\angle DFE = \angle E =90-\dfrac{y}{2}

The two angles of \triangle EDF are equal hence \triangle EDF is isosceles.

8 0
3 years ago
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