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3 years ago

3. If a ladder is x feet long, how high up a wall can it safely reach?

Mathematics

1 answer:

sineoko [7]3 years ago

6 0

Answer:

xsin∅

Step-by-step explanation:

If the ladder is <em>x foot long</em>, and it can safely make a <em>maximum angle ∅</em> with the floor, then, the maximum height it can reach will be xsin∅

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A student bought 3 boxes of pencils and 2 boxes of pens for $6. He then bought 2 boxes of pencils and 4 boxes of pens for $8. Fi

Annette [7]

Let c and n represent the numbers of pencil and pen boxes, respectively
.. 3c +2n = 6.00
.. 2c +4n = 8.00

You can halve the second equation and subtract it from the first to get
.. (3c +2n) -(c +2n) = 6.00 -4.00
.. 2c = 2.00
.. c = 1.00

Then
.. 1.00 +2n = 4.00 . . . . . half the original second equation with c filled n
.. 2n = 3.00
.. n = 1.50

A box of pencils costs $1.00; a box of pens costs $1.50.

8 0

3 years ago

Read 2 more answers

. For the function y= -5x2 - 10x + c, the vertex is (-1,8). What is c? F. -13 G. -3 - J. 13 H. 3

Marrrta [24]

Answer:

c=3

Step-by-step explanation:

8=-5(-1)^2-10(-1)+c

8=5+c

c=3

4 0

3 years ago

Write the slope-intercept form of the equation that passes through the point (-3, 5) and is perpendicular to the line y = 1/5x +

aleksley [76]

Answer:

Step-by-step explanation:

$\text{Let}\\\\k:y=m_1x+b_1\\\\l:y=m_2x+b_2\\\\l\ \perp\ k\iff m_1m_2=-1\to m_2=-\dfrac{1}{m_1}\\\\l\ \parallel\ k\iff m_1=m_2\\\\=========================$

$\text{We have}\ y=\dfrac{1}{5}x+10\to m_1=\dfrac{1}{5}\\\\\text{Therefore}\ m_2=-\dfrac{1}{\frac{1}{5}}=-5.\\\\\text{Put the value of a slope and the coordinates of the point (-3, 5)}\\\text{to the equation}\ y=mx+b:\\\\5=-5(-3)+b\\5=15+b\qquad\text{subtract 15 from both sides}\\-10=b\to b=-10\\\\\text{Finally:}\\\\y=-5x-10$

7 0

3 years ago

19. If 1:3=4:x, then what is the value of x<br>9<br>12<br>4/3<br><br>15

gulaghasi [49]

Answer:

Step-by-step explanation:

1 : 3 : : 4: x

Multiply 1 and x and multiply 3 and 4

x = 12

7 0

3 years ago

Simplify each algebraic expression.

GREYUIT [131]

Answer:

$\huge\boxed{\sf-2x+28}\\\\\huge\boxed{\sf 10x-4}\\\\\huge\boxed{\sf 56-5x}\\\\\huge\boxed{\sf x-13}$

Step-by-step explanation:

$\sf 2x + 4(7-x) \\\\Resolving \ Parenthesis\\\\2x + 28-4x \\\\Combining\ like\ terms\\\\2x-4x +28\\\\-2x + 28\\\\\rule[225]{225}{2}$

$\sf \\12x-(4+2x)\\\\12x-4-2x\\\\Combining \ like \ terms\\\\12x-2x - 4\\\\10x-4 \\\\\rule[22]{225}{2} \\2(10-x)+3(12-x) \\\\Resolving \ Parenthesis\\\\20-2x + 36 -3x\\\\Combining \ like \ terms\\\\20+36 -2x-3x\\\\56 - 5x \\\\\rule[225]{225}{2}$

$\sf 7(x-1)-6(x+1)\\\\Resolving \ Parethesis\\\\7x-7-6x-6\\\\Combining \ like \ terms\\\\7x-6x-7-6\\\\x - 13\\\\\rule[225]{225}{2}$

Hope this helped!

~AnonymousHelper1807

3 0

3 years ago