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Marat540 [252]
2 years ago
10

A purse originally cost $45.99. This week, it is on sale for 25% off.

Mathematics
2 answers:
sertanlavr [38]2 years ago
8 0

Answer: A

Step-by-step explanation:

Svet_ta [14]2 years ago
4 0
If you take 45.99 and minus 25% you would get 11.50 so your answer is A
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Will and Mohammed are playing a game where they roll a fair six-sided die and a fair four-sided die and try to predict the outco
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5 0
3 years ago
Read 2 more answers
Christine went shopping and bought each of her eighteight nephews a​ gift, either a video costing​ $14.95 or a CD costing​ $16.8
pogonyaev
So I think you should set up an equation like this: 14.95x+16.88y=131.18 , x+y=8

so x=8-y, plug this into the original equation:
14.95(8-y)+16.88y=131.18
Evaluate: 119.60-14.95y+16.88y=131.18
Combine like terms: 119.60+1.93y=131.18
Subtract 119.60 from both sides. You get: 1.93y=11.58
Divide both sides by 1.93. You get y=6

Plug into second equation: x+y=8 ---> x+6=8 and solve for x. x=2

Christine bought 2 video games and 6 CDs. 14.95(2)+16.88(6)=131.18
4 0
3 years ago
A small combination lock on a suitcase has 4 ​wheels, each labeled with the 10 digits 0 to 9. how many 4 digit combinations are
tamaranim1 [39]
This is the easiest way to solve this problem:

Imagine this represents how many combinations you can have for each of the 4 wheels (each blank spot for one wheel): __ __ __ __

For the first situation it says how many combos can we make if no digits are repeated.
We have 10 digits to use for the first wheel so put a 10 in the first slot 
10 __ __ __
Since no digit can be repeated we only have 9 options for the second slot
10 9_ __ __
Same for the third slot, so only 8 options
<u>10</u> <u> 9 </u> <u> 8 </u> __
4th can't be repeated so only 7 options left
<u>10</u> <u> 9 </u> <u> 8 </u> <u> 7 
</u><u>
</u>Multiply the four numbers together: 10*9*8*7 = 5040 combinations


For the next two do the same process as the one above.

If digits can be repeated? You have ten options for every wheel so it would look like this: <u>10</u> <u>10</u> <u>10</u> <u>10
</u>
10*10*10*10 = 10,000 combinations

If successive digits bust be different?
We have 10 for the first wheel, but second wheel only has 9 options because 2nd number can't be same as first. The third and fourth wheels also has 9 options for the same reason.

<u>10</u> <u> 9</u><u> </u> <u> 9 </u> <u> 9 </u>

10*9*9*9 = 7290 combinations






8 0
3 years ago
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