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Ugo [173]
3 years ago
10

This is urgent! It would really be helpful if you could help me:) Please and thank you!

Mathematics
1 answer:
amid [387]3 years ago
6 0

Answer:

the answer would be a

Step-by-step explanation:

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Use the graph to determine the domain and range of the relation, and whether the relation is a function
ohaa [14]
The answer is C. The domain is all points between -8 and 8 since it keeps waving back and forth. The range is all real numbers the graph continues on forever. And it is not a function because it does not pass the vertical line test
6 0
3 years ago
Please help meeeeeee​
otez555 [7]

Answer: its 1/4 per minute i took the test

Step-by-step explanation:

7 0
3 years ago
A car is travelling at exactly 6 miles per hour and accelerates at a constant rate to exactly 65 miles per hour.
vichka [17]

Answer:

14878.04878miles/hours^2

Step-by-step explanation:

Let's find a solution by understanding the following:

The acceleration rate is defined as the change of velocity within a time interval, which can be written as:

A=(Vf-Vi)/T where:

A=acceleration rate

Vf=final velocity

Vi=initial velocity

T=time required for passing from Vi to Vf.

Using the problem's data we have:

Vf=65miles/hour

Vi=6miles/hour

T=14.8seconds

Using the acceleration rate equation we have:

A=(65miles/hour - 6miles/hour)/14.8seconds, but look that velocities use 'hours' unit while 'T' uses 'seconds'.

So we need to transform 14.8seconds into Xhours, as follows:

X=(14.8seconds)*(1hours/60minutes)*(1minute/60seconds)

X=0.0041hours

Using X=0.0041hours in the previous equation instead of 14.8seconds we  have:

A=(65miles/hour - 6miles/hour)/0.0041hours

A=(61miles/hour)/0.0041hours

A=(61miles)/(hour*0.0041hours)

A=61miles/0.0041hours^2

A=14878.04878miles/hours^2

In conclusion, the acceleration rate is 14878.04878miles/hours^2

7 0
3 years ago
Hi again here's the picture
pshichka [43]

Answer:

<h2>351.88 m</h2>

Step-by-step explanation:

Given,

D = diameter of semicircular part = 42 m

L = Length of straight part = 110 m

Now, let's find the perimeter:

= 2 ( length of semi-circle + length of straight part )

= 2( \frac{\pi \: d}{2}  + l)

Plug the values

= 2( \frac{3.14  \times 42}{2}  + 110)

Calculate the product

= 2( \frac{131.88}{2}  + 110)

Divide

= 2 (65.94 + 110)

Calculate the sum

= 2 \times 175.94

Calculate

= 351.88 \: m

Hope this helps..

Best regards!!

8 0
3 years ago
Read 2 more answers
In ΔUVW, the measure of ∠W=90°, UV = 71 feet, and VW = 11 feet. Find the measure of ∠V to the nearest degree
Artyom0805 [142]

Answer:

81°

Step-by-step explanation:

Please refer to the attachment(s) for explanations

5 0
3 years ago
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