Answer:
The initial temperature of the object was 37.6
Step-by-step explanation:
we have

where
f(t) represent the temperature of the object in degree Celsius
t is the time in minutes
Find the value of the constant C
we have the ordered pair (4,35)
substitute in the equation and solve for C

Find the initial value of the object
we know that
The initial temperature is the value of f(t) when the value of t is equal to zero
so
For t=0

therefore
The initial temperature of the object was 37.6 (I not include units)
<span>15-h)*h=40
15h-h^2=40
h^2-15h+40=0
solve for h by quadratic formula:
a=1, b=-15, c=20
ans:
h=3.47 or 11.53 cm (height)
b=15-h=11.53 or 3.47 cm (base)</span>