Answer:
2) distance = 4 km
Displacement = 4 km east
3) distance = 35 km
Displacement = 5 km north
Step-by-step explanation:
2. He runs for 3 km in the east direction and then stops.. He now runs another 1 km in the same direction then stops.. Thus,
Total distance covered = 3 + 1 = 4 km
Total displacement is how far he is from his starting point = 3 + 1 = 4 km east
3) Runs 20km north and then runs 15 km back from starting point.
Thus;
Total distance covered = 20 + 15 = 35 km
Total displacement is distance from starting point = 20 - 15 = 5 km north
Subtracted because an opposite direction was taken after the 20km back to her starting point.
Answer:
15 miles
Step-by-step explanation:
Let's say the dock is at the origin on a coordinate plane and each unit is 1 mile. If the boat travels 9 mile due north, that means that we move up from the origin (0, 0) 9 units to point A (0, 9). Now, this boat moves 12 miles due west, so we will go 12 units to the left of (0, 9) to point B (-12, 9). See the attached drawing (sorry for the crudeness).
Notice that this is a right triangle with legs of 9 and 12. That means the distance from the boat to the dock is just the hypotenuse, so use the Pythagorean Theorem: distance = 
Thus, the answer is 15 miles.
Hope this helps!
\left[x \right] = \left[ -18\right][x]=[−18]equation of a line that is parallel
Answer is answer 17 plus 78
4- 2/3 (4-1/6) divided by 3/4
parenthesis first
4 - 2/3 (3 5/6) divided by 3/4
change to an improper fraction (6*3+5)/6
4 - 2/3 ( 23/6)divided by 3/4
4 - 46/18 divide by3/4
copy dot flip
4 - 46/18 * 4/3
4 - 23/9 * 4/3
4 - 92/27
get a common denominator of 27
4*27/27 -92/27
108/27 - 92/27
16/27
