All categories

4 years ago

How does the value of the digit 4 in 3.546 compare to the value of the digit 4 in 4.23

Mathematics

1 answer:

JulijaS [17]4 years ago

3 0

Answer:

the digit 4 in 3.546 is called hundredth because it is after the decimal point you add -th behind it while the digit 4 in 4.23 is called a unit

You might be interested in

Is the product of two integers positive, negative , or zero ? How can you tell?

Firlakuza [10]

Answer:it depends on the numbers you are using.

Step-by-step explanation:

6 0

3 years ago

If you conducted a survey on the distribution of M & M colors in 20 packages chosen at random, what type of graph would be b

navik [9.2K]

Answer:

A bar graph is the best graph to use

5 0

3 years ago

(EASY) I WILL MARK THE BRAINLYEST !!!

nydimaria [60]

Answer:

-8>x>6

Step-by-step explanation:

I 5x+5I +22> 57subtract 22 on both sides

I5x+5I >35

SPLIT

5x+5>35 5x+5< -35 ( flip sign and 35 negative)

5x>30 5x< -40

x>6 x< -8

Draw a number line Write zero in the middle

From zero count to the left until- 8 make an open circle because- 8 is not included From -8 draw an arrow to the left (because x is less than -8)

From zero count to the right until 6 Make an open circle bc 6 is not included. From 6 draw an arrow to the right (because x is more than 6)

PART 2 is not already solved?

If you need to solve fot t

Divide both parts by pr

t= (l/ pr)

4 0

3 years ago

Suppose the half-life of a material is 10 days. You have one 1 kg of the material today. How much of the material would you have

boyakko [2]

Answer:

0.50 kg of the material would be left after 10 days.

0.25 kg of the material would be left after 20 days.

Step-by-step explanation:

We have been given that the half-life of a material is 10 days. You have one 1 kg of the material today. We are asked to find the amount of material left after 10 days and 20 days, respectively.

We will use half life formula.

$A=a\cdot(\frac{1}{2})^{\frac{t}{h}}$ , where,

A = Amount left after t units of time,

a = Initial amount,

t = Time,

h = Half-life.

$A=1\text{ kg}\cdot(\frac{1}{2})^{\frac{10}{10}}$

$A=1\text{ kg}\cdot(\frac{1}{2})^{1}$

$A=1\text{ kg}\cdot\frac{1}{2}$

$A=0.5\text{ kg}$

Therefore, amount of the material left after 10 days would be 0.5 kg.

$A=1\text{ kg}\cdot(\frac{1}{2})^{\frac{20}{10}}$

$A=1\text{ kg}\cdot(\frac{1}{2})^{2}$

$A=1\text{ kg}\cdot\frac{1^2}{2^2}$

$A=1\text{ kg}\cdot\frac{1}{4}$

$A=0.25\text{ kg}$

Therefore, amount of the material left after 20 days would be 0.25 kg.

6 0

3 years ago

Suppose a wristband has a circumference of 7.5 inches. What is the radius of the wristband to the nearest hundredth of an inch?

andrezito [222]

The answer is b uh it’s 4 in the morning I hope this helped and I hope you can still answer the question

6 0

3 years ago