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meriva
3 years ago
13

Andy and Samantha are performing an experiment in a science lab. The number of bacteria cells recorded by Andy in his experiment

is represented by the equation below, where B represents the number of bacteria, x hours after beginning the experiment.
B = 6x + 5

The number of bacteria cells recorded by Samantha in her experiment is represented by the equation below, where B represents the number of bacteria, x hours after beginning the experiment.

B = 2^x + 3
Using graphing technology, complete the statements.


After answer hours, the total number of bacteria cells for both experiments will be the same.


The total number of bacteria cells at that hour will be answer .

Mathematics
2 answers:
-Dominant- [34]3 years ago
7 0
Andy will record 6x + 5 bacteria cells, while Samantha will record 2^x + 3 bacteria cells. These will be equal at a time when:
6x + 5 = 2^x + 3
Plotting both of these shows that they are equal when x = 5 and y = 35.
Therefore, the number of bacteria cells will be equal at 35, at t = 5 hours.

Mekhanik [1.2K]3 years ago
4 0

Answer:B = 6x + 5




Step-by-step explanation:


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Answer:

\sf t_{20}= 0

Step-by-step explanation:

<h3>Arithmetic sequence:</h3>

      \sf \boxed{\bf n^{th} \ term = a + (n-1)d}\\\\\text{Here, a is the first term ; d is the common difference }

6th term is 14 ⇒ \sf t_6 = 14

                a + (6 - 1)d = 14

                    a  +  5d = 14  --------------(I)

14th term is 6 ⇒\sf t_{14} = 6

             a + (14-1)d = 6

                  a + 13d = 6 ----------------(II)

Subtract equation (II) from equation(I)

        (I)          a + 5d = 14

        (II)         a + 13d = 6

                    <u>-    -          -</u>

                            -8d = 8

                               d  = 8 ÷(-8)      

                              \sf \boxed{\bf d= (-1)}

Plugin d = -1 in equation (I)

a + 5(-1) = 14

      a -5  = 14

             a = 14 + 5

             \sf \boxed{\bf a = 19}  

20th term:

 \sf t_{20}= 19 + 19*(-1)

       = 19 - 19

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Answer:

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Solution:

Given data:

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$t=\frac{-48\pm \sqrt{48^2-4(-16)(288)}}{2(-16)}

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