Given:
15. 
17. 
19. 
To find:
The values of the given logarithms by using the properties of logarithms.
Solution:
15. We have,

Using property of logarithms, we get
![[\because \log_aa=1]](https://tex.z-dn.net/?f=%5B%5Cbecause%20%5Clog_aa%3D1%5D)
Therefore, the value of
is 1.
17. We have,

Using properties of logarithms, we get
![[\because \log_a\dfrac{m}{n}=-\log_a\dfrac{n}{m}]](https://tex.z-dn.net/?f=%5B%5Cbecause%20%5Clog_a%5Cdfrac%7Bm%7D%7Bn%7D%3D-%5Clog_a%5Cdfrac%7Bn%7D%7Bm%7D%5D)
![[\because \log_aa=1]](https://tex.z-dn.net/?f=%5B%5Cbecause%20%5Clog_aa%3D1%5D)
Therefore, the value of
is -1.
19. We have,

Using property of logarithms, we get
![[\because a^{\log_ax}=x]](https://tex.z-dn.net/?f=%5B%5Cbecause%20a%5E%7B%5Clog_ax%7D%3Dx%5D)
Therefore, the value of
is 100.
First, you take 36 counters and spread them out. You then separate them into groups of 8 and any left that cannot be separated into groups of 8 are the remainders. When you do this, you will find that you are able to separate 36 into 4 groups of eight, and you will get a remainder of 4, so your answer is 4 remainder 4
The answer is: "10 cm" .
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Method 1)
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2L + 2w = 40 ; Since the formula for perimeter of a rectangle (Note: a square is a rectangle) is:
P = 2L + 2w ; Note: L = length; w = width; P = perimeter;
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Factor out a "2":
_________________
" 2L + 2w = 40" ;
2 (L+ w) = 40;
Divide each side of the question by "2" ;
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[2 (L + w)] / 2 = 40 / 2 ;
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to get: (L + w) = 20 ;
Note: this "rectangle is a square" ; so L= w".
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20 /2 = 10 ;
L + w = 10 + 10 = 20.
This is a square, so each side of the square is the same length.
Each side is: 10 cm .
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Method 2)
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We are given: The perimeter (sum of the lengths of all sides) of a square is "40 cm." Since a square has 4 sides of equal length:
Each side is: 40 cm / 4 = 10 cm.
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Answer:
(A) 0.006593 or 0.6593%
(B) 0.01538 or 1.538%
Step-by-step explanation:
The total number of possibilities to pick 3 parts out of 15 possible parts is given by the following combination:

(A) There are only three possibilities for which the inspector finds exactly one nonconforming part (NCC, CNC, CCN). Therefore, the probability is:

(B) There are three possibilities for which the inspector finds exactly one nonconforming part, three possibilities for two nonconforming parts (NNC, CNN, NCN), and one possibility for all nonconforming parts (NNN). The probability that the inspector finds at least one nonconforming part is:

Answer:
C.
Step-by-step explanation:
the given graph touches the Y-axis in the point (5;0), it means the only zero.
To the additional: the graph is y=(x-5)².