What is the interquartile range of the sequence 5,5,8,8,13,14,16,16,19,22,23,27,31 ?
Romashka-Z-Leto [24]
Answer:
The Interquartile range is 10.
Step-by-step explanation:
First, we will need to find the mean, the mean of this sequence is 16, you will now need to find quartile 1 and quartile 3. Quartile 1 is 13, and quartile 3 is 23. Lastly, subtract Quartile 3 and Quartile 1 will be the answer.
So, 23-13=10
The Answer will be 10, the interquartile range is 10.
Hope this helps!
Answer:
36+64=100 100 to the square root is 10
Step-by-step explanation:
I'm not giving a diagram just draw a triangle and make the base of it 8 and the length of it 6 but the diagonal part 10
It's the pythagorean theorum. a^2 + b^2 = c^2
^2= to the 2nd power. or squared.
In this case it really doesnt matter which one you label for this part of math.
so 8^2 + 6^2 = C^2 where C is the shortest distance between the houses.
and 8 and 6 were the lengths given.
64+36=100
100's square root is 10 because 10^2 is 100 or 10*10 is 100. If you dont know what squaring is.
Its multiplying something by that something once so 1 squared is 1 because its 1*1 you are multiplying it once 2 squared or 2^2 is 4 because 2*2 is 4 3 squared or 3^2 is 9 because 3*3 is 9. 4 squared is 16 because 4*4 is 16. and if you did 2 to the power of 3 of 2 cubed it would be 8 because 2*2*2 is 8.
The answer is R=0.053707443....
Round to the nearest decimal place as it asks for
i hope this helps :)
