To find the average number of books donated per month, we first get the total number of books that Eric has donated within the span of (8 - 3) = 5 months.
Since from 157 books, there were only 102 books left after 5 months, that means he has donated (157 - 102) = 55 books.
That means that he has donated 55 books within the span of 5 monhs. Thus, the average number of books would be equal to (number of books) / (number of months) = 55 / 5 = 11 books per month.
<span>Answer: 11 books</span>
Step-by-step explanation:
wheres the decimal to compare it to
Answer:
10
Step-by-step explanation:
you take 2 times 5
Hello :
the nth term ( general term of an arithmetic sequence is :
An =A1+(n-1)d ....a common difference is : d , A1 : the first terme
A1 = 5 and : d = 1 - 5 = - 4 n = 21
A21 = 5 + (21 -1)(-4)
A21 = 5 - 80 = -75
<span>
</span>
<span>(5+2 i)(4-3i) - (5-2yi)(4-3i)
Factorize out (4 -3i)
(4 -3i)( (5 +2i) - (5 -2yi) )
= </span><span><span>(4 -3i)(5 +2i - 5 + 2yi)</span>
= </span><span><span>(4 -3i)(5 - 5 + 2i + 2yi)</span>
= (4 -3i)(2i + 2yi)
= (4 - 3i)(2 + 2y)i. Let's multiply the first two.
</span>
(4 - 3i)(2 + 2y) = 2*(4 -3i) + 2y*(4 - 3i)
= 8 - 6i + 8y - 6yi
= 8 + 8y - 6i - 6yi
(4 - 3i)(2 + 2y)i = (8 + 8y - 6i - 6yi)i Note: i² = -1
= 8i + 8yi - 6i² - 6yi²
= 8i + 8yi - 6(-1) - 6y(-1)
= 8i + 8yi + 6 + 6y
= 6 + 6y + 8i + 8yi
= (6 + 6y) + (8 + 8y)i In the form a + bi
