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Arada [10]
3 years ago
15

I’m trying to correct this problem but I don’t know how can someone help me

Mathematics
1 answer:
BartSMP [9]3 years ago
6 0

Remark

It is not a straight line distance from the park to the mall. None of the answers give you that result. And if you know what displacement is, none of the answers are really displacement either. The distance is sort of a "as the crow flies." distance. There's a stop off in the middle of town.

Method

You need to use the Pythagorean Formula twice -- once from the park to the city Center and once from the city center to the mall.

Distance from the Park to the city center.

a = 3   [distance east]

b = 4  [distance south]

c = ??

c^2 = 3^2 + 4^2        Take the square root of both sides.

c = sqrt(3^2 + 4^2)

c = sqrt(9 + 16)          Add

c = sqrt(25)

c = 5

So the distance from the park to the city center is 5 miles

Distance from City center to the mall

a = 2 miles [distance east]

b = 2 miles [distance north]

c = ??

c^2 = a^2 + b^2   Substitute

c^2 = 2^2 + 2^2   Expand this.

c^2 = 4 + 4

c^2 = 8             Take the square root of both sides.

sqrt(c^2) = sqrt(8)

c = sqrt(8)          This is the result

c = 2.8

Answer

Total distance = 5 + 2.8 = 7.8

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Probability that a customer pays the bill by mail, given that the customer is female is 0.20.

Step-by-step explanation:

The complete question is:

                               Online                             By Mail            Total

             Male             12                                      8                   20

           Female           24                                     6                   30      

             Total             36                                     14                  50    

A utility company asked 50 of its customers whether they pay their bills online or by mail. What is the probability that a customer pays the bill by mail, given that the customer is female.

Probability that a customer pays the bill by mail, given that the customer is female is given by = P(Pays bill by mail / Customer is female)

\frac{6}{50}P(Pays bill by mail/Customer is female) = \frac{P(\text{Pays bill by Mail}\bigcap \text{ Customer is Female})}{P(\text{ Customer is Female})}

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Also, Probability that customer pays bill by mail and is female =   \frac{6}{50}

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                                         =  \frac{6}{50}\times \frac{50}{30}

                                         =  \frac{1}{5}   =  0.20

Hence, probability that a customer pays the bill by mail, given that the customer is female is 0.20.

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