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3 years ago

Erika ran 2 miles in 18 mintes and 3 miles in 27 minutes

Mathematics

2 answers:

Stells [14]3 years ago

8 0

In she ran 5miles and 45minutes

Montano1993 [528]3 years ago

7 0

Therefore? What needs to be solved?

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A slope of -5 that passes through (2,15)

amm1812

Answer:

y=-5x+25

That is the answe in slope intercept form

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3 years ago

Which expression is equivalent to (18)2⋅(19)2

sladkih [1.3K]

The expression that is equivalent to the given expression where the expression is given as (18)2⋅(19)2 is (18 * 19)^2

<h3>How to determine which expression is equivalent to the given expression? </h3>

The expression is given as

(18)2⋅(19)2

Rewrite the above expression properly

So, we have

(18)^2 * (19)^2

The factors in the above expression have the same exponent.

So, the expression can be rewritten as

(18 * 19)^2

Hence, the expression that is equivalent to the given expression where the expression is given as (18)2⋅(19)2 is (18 * 19)^2

Read more about equivalent expression at

brainly.com/question/2972832

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1 year ago

Complete the proof using paragraph or two-column, or flow. Please help me! Answer ASAP!

Alenkasestr [34]

The answer is in the photo. Hope this helps

4 0

3 years ago

The following data comparing wait times at two rides at Disney are listed below: Position Pirates Splash Mountain Sample Size 32

myrzilka [38]

Answer:

a) $(14.68 -18.77) - 2.39 \sqrt{\frac{11.87^2}{32}+\frac{16.79^2}{30}} =-12.968$

$(14.68 -18.77) + 2.39 \sqrt{\frac{11.87^2}{32}+\frac{16.79^2}{30}} =4.788$

b) $t=\frac{14.68-18.77}{\sqrt{\frac{11.87^2}{32}+\frac{16.79^2}{30}}}}=-1.10$

Step-by-step explanation:

Data given and notation

$\bar X_{A}=14.68$ represent the mean for Pirates

$\bar X_{B}=18.77$ represent the mean for Splash Mountain

$s_{A}=11.87$ represent the sample standard deviation for the sample Pirates

$s_{B}=16.79$ represent the sample standard deviation for the sample Slpash Mountain

$n_{A}=32$ sample size selected for Pirates

$n_{B}=30$ sample size selected for Splash Mountain

$\alpha=0.02$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

Part a

The confidence interval would be given by:

$(\bar X_A -\bar X_B) \pm t_{\alpha/2} \sqrt{\frac{s^2_{A}}{n_{A}}+\frac{s^2_{B}}{n_{B}}}$

The degrees of freedom are given by:

$df = n_A +n_B -2 = 32+30-2 = 60$

Since we want 98% of confidence the significance level is $\alpha =1-0.98 =0.02$ and $\alpha/2 =0.01$ , we can find in the t distribution with df =60 a critical value that accumulates 0.01 of the area on each tail and we got:

$t_{\alpha/2}= 2.39$

And replacing we got for the confidence interval:

$(14.68 -18.77) - 2.39 \sqrt{\frac{11.87^2}{32}+\frac{16.79^2}{30}} =-12.968$

$(14.68 -18.77) + 2.39 \sqrt{\frac{11.87^2}{32}+\frac{16.79^2}{30}} =4.788$

Part b

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the means are equal, the system of hypothesis would be:

Null hypothesis: $\mu_{A} = \mu_{B}$

Alternative hypothesis: $\mu_{A} \neq \mu_{B}$

the statistic is given by:

$t=\frac{\bar X_{A}-\bar X_{B}}{\sqrt{\frac{s^2_{A}}{n_{A}}+\frac{s^2_{B}}{n_{B}}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other".

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{14.68-18.77}{\sqrt{\frac{11.87^2}{32}+\frac{16.79^2}{30}}}}=-1.10$

6 0

3 years ago

9. If PQRS is a kite, find RQ. *<br><br> 17 ft.<br> 23 ft.<br> 30 ft.<br> 12 ft.

svetlana [45]

Answer:

17 ft

Step-by-step explanation:

The triangle on the bottom left is a right triangle.

a² + b² = c²

(8 ft)² + (15 ft)² = (RQ)²

64 ft² + 225 ft² = (RQ)²

(RQ)² = 289 ft²

RQ = 17 ft

4 0

2 years ago

Erika ran 2 miles in 18 mintes and 3 miles in 27 minutes​

Erika ran 2 miles in 18 mintes and 3 miles in 27 minutes