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yanalaym [24]
3 years ago
10

Danielle earns a 7.25% commission on everything she sells at the electronics store where she works. She also earns a base salary

of $625 per week. How much did she earn last week if she sold $4,500 in electronics merchandise? Round your intermediate calculations and answer to the nearest cent
Mathematics
1 answer:
sashaice [31]3 years ago
8 0

Danielle earned $951.25

Step-by-step explanation:

Multiply her commission by her sales and add her base rate

x=7.25%($4500)+625 or x=0.0725(4500)+625

distribute

x=326.25+625

simplify

x=951.25

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maw [93]

The result of the given parameters is -653/3

<h3>Solving expression</h3>

Given the following parameter

-4(1 + 5)²/6 - (42 +5)

Expand the parenthesis

-4(16)²/6 - (47)

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Simplify the resulting expression

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-1024-282/6

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-653/3

Hence the result of the given parameters is -653/3

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5 0
1 year ago
A car is being tested for reliability on a track by driving at a constant speed for 5 hours straight. So far, the car has travel
yarga [219]

Answer:

speed=88m/k

Step-by-step explanation:

8 0
3 years ago
Find the volume of the region between the planes x plus y plus 2 z equals 2 and 4 x plus 4 y plus z equals 8 in the first octant
Alex787 [66]

Find the intercepts for both planes.

Plane 1, <em>x</em> + <em>y</em> + 2<em>z</em> = 2:

y=z=0\implies x=2\implies (2,0,0)

x=z=0\implies y=2\implies(0,2,0)

x=y=0\implies 2z=2\implies z=1\implies(0,0,1)

Plane 2, 4<em>x</em> + 4<em>y</em> + <em>z</em> = 8:

y=z=0\implies4x=8\implies x=2\implies(2,0,0)

x=z=0\implies4y=8\impliesy=2\implies(0,2,0)

x=y=0\implies z=8\implies(0,0,8)

Both planes share the same <em>x</em>- and <em>y</em>-intercepts, but the second plane's <em>z</em>-intercept is higher, so Plane 2 acts as the roof of the bounded region.

Meanwhile, in the (<em>x</em>, <em>y</em>)-plane where <em>z</em> = 0, we see the bounded region projects down to the triangle in the first quadrant with legs <em>x</em> = 0, <em>y</em> = 0, and <em>x</em> + <em>y</em> = 2, or <em>y</em> = 2 - <em>x</em>.

So the volume of the region is

\displaystyle\int_0^2\int_0^{2-x}\int_{\frac{2-x-y}2}^{8-4x-4y}\mathrm dz\,\mathrm dy\,\mathrm dx=\displaystyle\int_0^2\int_0^{2-x}\left(8-4x-4y-\frac{2-x-y}2\right)\,\mathrm dy\,\mathrm dx

=\displaystyle\int_0^2\int_0^{2-x}\left(7-\frac72(x+y)\right)\,\mathrm dy\,\mathrm dx=\int_0^2\left(7(2-x)-\frac72x(2-x)-\frac74(2-x)^2\right)\,\mathrm dx

=\displaystyle\int_0^2\left(7-7x+\frac74 x^2\right)\,\mathrm dx=\boxed{\frac{14}3}

3 0
3 years ago
Which one is larger .083 or .08 ?
fredd [130]

Answer:

.083 is larger.

Step-by-step explanation:

To find out the solution, add a zero to the .08.

.080

.083

As you can see, the 3 is larger than the zero. This concludes with .083 larger than .080.

3 0
3 years ago
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Klio2033 [76]

Answer:

B. two-thirds

Hope this helped :)

5 0
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