Answer: 6.71
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Work Shown:
The longest horizontal portion of length 6 breaks up into two equal pieces of length 3 each. Focus on the smaller right triangle on the right hand side. This right triangle has legs of 3 and 6. The hypotenuse is x.
Use the pythagorean theorem with a = 3, b = 6, c = x to find the value of x
a^2 + b^2 = c^2
3^2 + 6^2 = x^2
9 + 36 = x^2
45 = x^2
x^2 = 45
x = sqrt(45)
x = 6.7082039
x = 6.71
The small number is 2 the large number is 11.
4(2)+11(3)=41
2(2)+11=15
11(10) -2(6) = 98
hope that helps
use the pythagorean theorem twice
alrighty
so
remember for legs length a and b and hytponuse c in a right triangle
a²+b²=c²
we need AD and DC
so
AD²+7.9²=9.4²
AD=√25.95
DC²+7.9²=23.2²
DC=√475.83
so
AD+DC=base=(√25.95)+(√475.83)≈26.9076
AC≈26.91 units
Answer:
x = 7
Step-by-step explanation:
Distribute the 2 on the right and the -1 on the left: 13 - 2x - 2 = 2x + 4 + 3x
Combine like terms on each side of the equation: 11 - 2x = 5x + 4
Add 2x to both sides, and subtract 4 from each side: 7 = 7x
Divide both sides by 7: x = 7
The values cannot be labeled as dependent or independent without a givin equation
