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s344n2d4d5 [400]
3 years ago
12

Solve for x: 3x - 5 = 2x + 6​

Mathematics
2 answers:
REY [17]3 years ago
7 0

Answer:

3x - 5 = 2x + 6  

Step one- Subtract 2x to isolate the variable  

X – 5 = 6  

 

Step two- Add 5 to continue to isolate the variable  

X = 11  

 

Your answer is      x = 11  

 

Hopefully this helps! Feel free to mark brainliest!

vlabodo [156]3 years ago
7 0

Answer: x=11

Step-by-step explanation:

3x-5=2x+6

+5. +5

3x=2x+11

-2x -2x

x=11

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Subtract 8 1/2 - 2 2/3 = ?
Andrews [41]

Answer: 2 2/3 or 2.6 repeating

Step-by-step explanation:

- Reduce the numbers With the greatest common divisor 2

- Calculate product

- Calculate the difference

- YOUR FINAL ANSWER

Hope I was able to satisfy your needs

8 0
3 years ago
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The cost of milk is expected to raise 106% over the next year
gulaghasi [49]

Answer: about $6.90


Step-by-step explanation: 106% of 3.35

100% of 3.35 is 3.35

6% of 3.35 is 0.201

Add them together and you get 3.551

When you round to the nearest cent, you get $3.55

After add 3.55 to 3.35 and you get $6.90


3 0
3 years ago
Triphasil-28 birth control tablets are taken sequentially, 1 tablet per day for 28 days, with the tablets containing the followi
bazaltina [42]

Answer:

1.925mg of levonorgestrel and 0.68mg of ethinyl estradiol are taken during the 28-day period.

Step-by-step explanation:

The total milligrams of levonorgestrel is:

L = L_{1} + L_{2} + L_{3}

In which L_{1}, L_{2} and L_{3} are the number of miligrams of levonorgestrel taken in each phase.

The total milligrams of ethinyl estradiol is:

E = E_{1} + E_{2} + E_{3}

In which E_{1},E_{2} and E_{3} are the number of miligrams of ethinyl estradiol taken in each phase.

We can solve this by phase.

Phase 1: 6 tablets, each containing 0.050 mg of levonorgestrel and 0.030 mg ethinyl estradiol

In this phase,

6*0.050mg = 0.30mg of levonorgestrel and 6*0.030mg = 0.18mg of ethinyl estradiol are taken.

So L_{1} = 0.30 and E_{1} = 0.18

Phase 2: 5 tablets, each containing 0.075 mg of levonorgestrel and 0.040 mg ethinyl estradiol

In this phase,

5*0.075mg = 0.375mg of levonorgestrel and 5*0.040mg = 0.20mg of ethinyl estradiol are taken.

So L_{2} = 0.375 and E_{2} = 0.20

Phase 3: 10 tablets, each containing 0.125 mg of levonorgestrel and 0.030 mg ethinyl estradiol

In this phase,

10*0.125mg = 1.25mg of levonorgestrel and 10*0.030mg = 0.30mg of ethinyl estradiol are taken.

So L_{3} = 1.25 and E_{3} = 0.30

The total milligrams of levonorgestrel is:

L = L_{1} + L_{2} + L_{3} = 0.30 + 0.375 + 1.25 = 1.925

The total milligrams of ethinyl estradiol is:

E = E_{1} + E_{2} + E_{3} = 0.18 + 0.20 + 0.30 = 0.68

1.925mg of levonorgestrel and 0.68mg of ethinyl estradiol are taken during the 28-day period.

6 0
3 years ago
What are the pattern conbination between these number 18 48 88 128 178 38 68
valentina_108 [34]
18+30=48
48+40=88
88+40=128
128+50=178

Thats all i found so far in the pattern
30,40,40,50
then it drops
by 140 then adds by 30..

I dont know how else to explain it
7 0
3 years ago
Help i need to pass:/
laila [671]

Answer:

biologists have a 14ft john boat with trolling motor for sale or trade for hipnopotomus

8 0
3 years ago
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