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4 years ago

12

Can you please help me

2 answers:

enot [183]4 years ago

8 0

Answer: the function would be graph #1

Step-by-step explanation:

when figuring out a function you can always use the vertical line test. that means putting a pencil over the graph and move it vertically across. if at any point in time the pencil touches more than one point on the line at the same time it is not a function

Alexeev081 [22]4 years ago

3 0

Answer:

graph 1

Step-by-step explanation:

no 2 points are on the save vertical line

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Answer:

$6.68

Step-by-step explanation:

83.50(0.08) = 6.68

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3 years ago

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Step-by-step explanation:

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3 years ago

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4 years ago

Solve for x 6x^2=2x-1

leva [86]

Answer:

$\displaystyle x=\frac{1\pm i\sqrt{5}}{6}$

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Equality Properties

<u>Algebra I</u>

Standard Form: ax² + bx + c = 0
Quadratic Formula: $\displaystyle x=\frac{-b\pm\sqrt{b^2-4ac} }{2a}$

<u>Algebra II</u>

Imaginary Roots: √-1 = i

Step-by-step explanation:

<u>Step 1: Define</u>

6x² = 2x - 1

<u>Step 2: Rewrite</u>

Subtract 2x on both sides: 6x² - 2x = -1
Add 1 to both sides: 6x² - 2x + 1 = 0

<u>Step 3: Identify Variables</u>

a = 6

b = -2

c = 1

<u>Step 4: Solve for </u><em><u>x</u></em>

Substitute [QF]: $\displaystyle x=\frac{2\pm\sqrt{(-2)^2-4(6)(1)} }{2(6)}$
Exponents: $\displaystyle x=\frac{2\pm\sqrt{4-4(6)(1)} }{2(6)}$
Multiplication: $\displaystyle x=\frac{2\pm\sqrt{4-24} }{12}$
(Square Root) Subtract: $\displaystyle x=\frac{2\pm\sqrt{-20} }{12}$
Factor: $\displaystyle x=\frac{2\pm \sqrt{-1} \sqrt{20} }{12}$
Simplify: $\displaystyle x=\frac{2\pm 2i\sqrt{5} }{12}$
Factor GCF: $\displaystyle x=\frac{2(1\pm i\sqrt{5} )}{12}$
Simplify: $\displaystyle x=\frac{1\pm i\sqrt{5}}{6}$

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3 years ago

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3 years ago

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