Write six and five hundredths in decimal form.

Mathematics

2 answers:

tia_tia [17]3 years ago

8 0

Answer:

6.05

Step-by-step explanation:

liq [111]3 years ago

7 0

6.05 = Sixty Five Hundreths

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1. Remember what we know about vertical angles and solve for x. (SHOW WORK)

marusya05 [52]

Answer:

Ans 1. $x= 7$

Ans 2.a.

$\overline {AC} \cong \overline {JL} \\\textrm{is the additional information required to prove the triangles are congruent by SAS postulate}$

Ans.2.b.

$\overline {BC} \cong \overline {KL} \\\textrm{is the additional information required to prove the triangles are congruent by the HL theorem}$

Step-by-step explanation:

Solution:

Vertically opposite angles are equal.

$\therefore (x+16) = (4x-5)\\\therefore (4x-x) = (16+5)\\\therefore (3x) = (21)\\\therefore x = 7$

2.a.

proof for Δ BAC ≅ ΔKJL by SAS postulate.

InΔ BAC and Δ KJL

BA ≅ KJ Given

∠ BAC ≅ ∠ KJL {measure each angle is 90}

$\overline{AC} \cong \overline{JL}\ \textrm{additional information require to prove the tangles are congruent by SAS postulate}\\\therefore \triangle BAC \cong \triangle KJL\ \textrm{By Side-Angle-Side postulate...PROVED}$

2.b.

proof for Δ BAC ≅ ΔKJL by HL theorem.

InΔ BAC and Δ KJL

BA ≅ KJ Given

∠ BAC ≅ ∠ KJL {measure each angle is 90}

$\overline{BC} \cong \overline{KL}\ \textrm{additional information require to prove the tangles are congruent by HL theorem}\\\therefore \triangle BAC \cong \triangle KJL\ \textrm{By Hypotenuse Leg Theorem......PROVED}$