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Lisa [10]
3 years ago
9

Click on the solution set graphic until the correct one is displayed. 1.{ } or empty set 2. {point in quadrant I} 3. {point in q

uadrant II

Mathematics
1 answer:
stepladder [879]3 years ago
3 0
1 {} empty set ..........
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Si: P(x+2) = 2(x+2)^3 + x^2 +4x +4<br> Calcular : P(-4)
Tom [10]

Answer:

Step-by-step explanation:

6 0
3 years ago
Find the two smallest possible solutions to part 1a​
bixtya [17]
<h3>Answer: A. 5/12, 25/12</h3>

============================

Work Shown:

12*sin(2pi/5*x)+10 = 16

12*sin(2pi/5*x) = 16-10

12*sin(2pi/5*x) = 6

sin(2pi/5*x) = 6/12

sin(2pi/5*x) = 0.5

2pi/5*x = arcsin(0.5)

2pi/5*x = pi/6+2pi*n or 2pi/5*x = 5pi/6+2pi*n

2/5*x = 1/6+2*n or 2/5*x = 5/6+2*n

x = (5/2)*(1/6+2*n) or x = (5/2)*(5/6+2*n)

x = 5/12+5n or x = 25/12+5n

these equations form the set of all solutions. The n is any integer.

--------

The two smallest positive solutions occur when n = 0, so,

x = 5/12+5n or x = 25/12+5n

x = 5/12+5*0 or x = 25/12+5*0

x = 5/12 or x = 25/12

--------

Plugging either x value into the expression 12*sin(2pi/5*x)+10 should yield 16, which would confirm the two answers.

7 0
3 years ago
Read 2 more answers
Find the product of (3^6)(3)(3^5) Express your answer using exponents
VikaD [51]

Answer:

3^12

Step-by-step explanation:

When multiplying the same number with different exponents you have to add the the exponents. For example:

a^x + a^y = a ^{x+y}

So (3^6)(3)(3^5) or (3^6)(3^1)(3^5) = 3^(6+1+5) = 3^12

6 0
3 years ago
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Solve for y.<br> 10 = 6 + y
frutty [35]
Y =4
if you replaced y with 4 the equation would be true...

it's easy math
- hope you have a nice day...
6 0
2 years ago
Read 2 more answers
Simplify 4 to the 11th power over 4 to the -8th power
madam [21]

Answer:

274878070200

Step-by-step explanation:

4 to the power 11 = 4194304

4 to the power -8 = 0.00001525878

4194304/0.00001525878 = 274878070200

3 0
3 years ago
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