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Lisa [10]
3 years ago
9

Click on the solution set graphic until the correct one is displayed. 1.{ } or empty set 2. {point in quadrant I} 3. {point in q

uadrant II

Mathematics
1 answer:
stepladder [879]3 years ago
3 0
1 {} empty set ..........
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Find the derivative.
Aleksandr [31]

Answer:

Using either method, we obtain:  t^\frac{3}{8}

Step-by-step explanation:

a) By evaluating the integral:

 \frac{d}{dt} \int\limits^t_0 {\sqrt[8]{u^3} } \, du

The integral itself can be evaluated by writing the root and exponent of the variable u as:   \sqrt[8]{u^3} =u^{\frac{3}{8}

Then, an antiderivative of this is: \frac{8}{11} u^\frac{3+8}{8} =\frac{8}{11} u^\frac{11}{8}

which evaluated between the limits of integration gives:

\frac{8}{11} t^\frac{11}{8}-\frac{8}{11} 0^\frac{11}{8}=\frac{8}{11} t^\frac{11}{8}

and now the derivative of this expression with respect to "t" is:

\frac{d}{dt} (\frac{8}{11} t^\frac{11}{8})=\frac{8}{11}\,*\,\frac{11}{8}\,t^\frac{3}{8}=t^\frac{3}{8}

b) by differentiating the integral directly: We use Part 1 of the Fundamental Theorem of Calculus which states:

"If f is continuous on [a,b] then

g(x)=\int\limits^x_a {f(t)} \, dt

is continuous on [a,b], differentiable on (a,b) and  g'(x)=f(x)

Since this this function u^{\frac{3}{8} is continuous starting at zero, and differentiable on values larger than zero, then we can apply the theorem. That means:

\frac{d}{dt} \int\limits^t_0 {u^\frac{3}{8} } } \, du=t^\frac{3}{8}

5 0
3 years ago
Why is the median not the best measurement to use in comparing these populations?
rodikova [14]
Because the medians are the same for both.
7 0
3 years ago
Theresa bought a new desktop computer. One side of the desktop screen is 14 inches and the
vazorg [7]

Answer:

23 inches

Step-by-step explanation:

assuming that the desktop screen is a rectangle, then it's diagonal will form two right triangles.

by the Pythagorean theorem

{a}^{2}  +  {b}^{2}  =  {c}^{2}  \\  a = 14 \: and \: b = 18 \\ c  = the \: hypoteneuse

then

{14}^{2}  +  {18}^{2}  =  {c}^{2}  \\ 196 + 324 =  {c}^{2}  \\ 520 =  {c}^{2}  \\  \sqrt{ {c}^{2} }  =  \sqrt{520}  \\ c   \: \: is \: a pprox. \:  \: 22.8 in \\ c \:  \: rounded \: is \: 23in

8 0
3 years ago
Please help!!!!!!!!!!!!!!!!!!!
VikaD [51]

Answer:

x = 5

Step-by-step explanation:

9(x-2) = 3(x+4)

9x - 18 = 3x + 12

9x = 3x + 30

6x = 30

x = 5

3 0
3 years ago
Marcie wants to enclose her yard with a fence. Her yard is in the shape of a triangle attached to a rectangle.
IRISSAK [1]
A>wh+bh/2
multiply both sides by 2
2A>2wh+bh
subtract 2wh from boths sides
2A-2wh>bh
divide both sides by h
(2A-2wh)/h>b
4 0
3 years ago
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