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3 years ago

What is the answer too -8(y-7) ?

Mathematics

1 answer:

PSYCHO15rus [73]3 years ago

8 0

Answer:

-8y -56

Step-by-step explanation:

Hope this helps! If it does, please mark me brainliest. Thank you! ;)

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A circus tent is cylindrical upto a height of 3.3 m and conical above it if the diameter of the base is 100m and slant height of

Rina8888 [55]

Total cost of canvas required in making the tent is rupees 79128

Solution:

Given:

Height of the cylindrical tent = h = 3.3 m

Diameter of it's base = d = 100m

$radius = \frac{diameter}{2} = \frac{100}{2} = 50$

r = 50 m

Curved surface area of cylinder:

$C.S.A = 2 \pi rh$

$C.S.A = 2 \times 3.14 \times 50 \times 3.3 = 1036.2$

Thus Curved surface area of cylinder = 1036.2 square meter

Curved surface area of cone:

$C.S.A = \pi rl$

$C.S.A = 3.14 \times 50 \times 56.4 = 8854.8$

Thus Curved surface area of cone = 8854.8 square meter

Total curved area of tent:

⇒ curved area of cone + curved area of cylinder

$\rightarrow 8854.8 + 1036.2=9891$

Thus total curved area of tent = 9891 square meter

find total cost of canvas required in making the tent:

The cost of canvas is 8 rupees per square meter

$\rightarrow \text{total cost } = 9891 \times 8 = 79128$

Thus total cost of canvas required in making the tent is rupees 79128

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3 years ago

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crimeas [40]

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3 years ago

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F is between E and G. Find FG if EG = 25, EF= 2x – 6 and FG = 4x + 7

KonstantinChe [14]

Answer:

23+ 37 = 42

the EG is congruent to the FA and therefore have to dividee the value to get 302

5 0

3 years ago

Find the quotient. 12a^3p^4 ÷ -2a^2p

777dan777 [17]

Answer:

-(6ap³)

Step-by-step explanation:

We have to find the quotients of

$\frac{12a^{3}p^{4}}{-2a^{2}p}$

We take the common 2a² p from the numerator

= $\frac{(6ap^{3}(2a^{2}p))}{(-2a^{2}p)}$

= -(6ap³)

Therefore, the quotient after division will be -(6ap³)

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3 years ago

Solve for t (88sin20) t-16t^2=0

vivado [14]

(88sin20)(t - 16t²) = 0
(8(0.3090169944)(t - 16t²) = 0
(2.472135955)(t - 16t²) = 0
2.472135955t - 39.55417528t² = 0

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3 years ago