Answer:
B, D, E and F are correct.
Step-by-step explanation:
B - PQ is parallel to RS. This is true as opposite sides of a rhombus are parallel.
D - PQR is supplementary to QPS. Two angles are supplementary when they add up to 180 degrees.
E - PR is perpendicular to QS. This is true because the diagonals of a rhombus bisect each other at right angles.
F - PS is parallel to QR. This is true as opposite sides of a rhombus are parallel.
Answer:
see explanation
Step-by-step explanation:
12
Since the denominators are like, add the numerators leaving the denominator
= 
= 
15
We require the denominators to be like before we can add.
factor x² - 4 as a difference of squares
x² - 4 = (x + 2)(x - 2)
Expressing as
+ 
multiply the numerator/denominator of the first fraction by (x - 2)
=
+ 
Expand and simplify the numerators, leaving the denominator
= 
= 
<h2>
Systems of Equations</h2>
To form a system of equation from a word problem, we must recognize different variables to form different equations.
<h2>Solving the Question</h2>
Let <em>a</em> represent the number of child tickets.
Let <em>b</em> represent the number of adult tickets.
We're given:
- 1a = $6.20
- 1b = $9.40
- a and b in total is 163
- Total sales = $1221.80
Because we're given that a and b in total is 163, we can form the following equation:

We're also given that the total sales made is $1221.80. Because we know that 1a = $6.20 and 1b = $9.40, we can also form the following equation:

Here are our two equations:


<h3>Solving the System of Equations</h3>
We can solve using the method of elimination. Multiply both sides by 6.2 in the first equation:

Subtract this new equation from the second equation to cancel out <em>a</em>:

Solve for <em>b</em>:

Therefore, the number of adult tickets sold is 66.
<h2>Answer</h2>
66
Answer:
Step-by-step explanation:
{5,7,9,11,13,15,17,19,21}
It goes on infinitely unless I did this wrong, if I did sorry:c
Answer: Given the 3 choices in the problem, the greatest profit would be for the final pair (6, 12).
If you input 6 for x in the function and 12 for y in the function, you will get an output profit value of 1260.
P = 50(6) + 80(12)
P = 300 + 960
On these types of problems, there are generally multiple constraints that you have to be aware of. One of the vertices of the possible areas must be (6, 12).