Weird way to write it but alright! (Sideways)
19pq^-2 x 5pq^6 = ?
These problems are pretty much single operations between each of the variables / constants.
So it's like this:
(19*5)(p*p)(q^-2*q^6) = ?
19*5 is 95.
For p*p remember that when two variables multiply there given powers add. In the case where the powers are not shown (like in the case of p*p) they are always assumed to be 1. So what is 1+1? 2.
p*p is p^2
For q^-2*q^6 it is the same deal with the previous problem. So now the problem looks like this:
-2 + 6 = 4
(The two is negative, because the power is negative 2)
So, q^4.
Our final answer is all of the combined.... like a so:
95p^2q^4
Answers
1) 1
2) 11
3) 4
4) D) Yes, the constant of variation is 3
Explanation
Q1
The slope of a line is given by
Slope = (change in y)/(change in x)
= (0 - -2)/(-4 - -6)
= 2/2
= 1
Q2
Slope = Δy/Δx
= (8 - -3)/(2 - 1)
= 11/1
= 11
Q3
Y varies directly as X. This is written as,
Y ∞ X
Put and equal sign then introduce the constant of proportionality, K.
Y = KX
K = Y/X
K = 6/18 = 1/3
∴ Y = (1/3)X
Y = (1/3) × 12
Y = 4
Q4
32Y = 96X
Dividing both sides by 32,
Y = 96/32 X
Y = 3X
3 been the constant, Y varies directly as X.
So, the equation 32y = 96x is a direct variation.
Constant of variation = 3
Answer:
3
Step-by-step explanation:
subtract 3y from both sides
add 9 to both sides
3y=12x+9
divide everything by 3
y=4x+3
y-intercept is 3
Let's simplify step-by-step.<span><span><span><span>5<span>x2</span></span>−<span>3x</span></span>−2</span>−<span>(<span><span><span>−<span>2<span>x2</span></span></span>−x</span>+10</span>)</span></span>Distribute the Negative Sign:<span>=<span><span><span><span>5<span>x2</span></span>−<span>3x</span></span>−2</span>+<span><span>−1</span><span>(<span><span><span>−<span>2<span>x2</span></span></span>−x</span>+10</span>)</span></span></span></span><span>=<span><span><span><span><span><span><span><span>5<span>x2</span></span>+</span>−<span>3x</span></span>+</span>−2</span>+<span><span>−1</span><span>(<span>−<span>2<span>x2</span></span></span>)</span></span></span>+<span><span>−1</span><span>(<span>−x</span>)</span></span></span>+<span><span>(<span>−1</span>)</span><span>(10)</span></span></span></span><span>=<span><span><span><span><span><span><span><span><span>5<span>x2</span></span>+</span>−<span>3x</span></span>+</span>−2</span>+<span>2<span>x2</span></span></span>+x</span>+</span>−10</span></span>Combine Like Terms:<span>=<span><span><span><span><span><span>5<span>x2</span></span>+<span>−<span>3x</span></span></span>+<span>−2</span></span>+<span>2<span>x2</span></span></span>+x</span>+<span>−10</span></span></span><span>=<span><span><span>(<span><span>5<span>x2</span></span>+<span>2<span>x2</span></span></span>)</span>+<span>(<span><span>−<span>3x</span></span>+x</span>)</span></span>+<span>(<span><span>−2</span>+<span>−10</span></span>)</span></span></span><span>=<span><span><span>7<span>x2</span></span>+<span>−<span>2x</span></span></span>+<span>−12</span></span></span>Answer:<span>=<span><span><span>7<span>x2</span></span>−<span>2x</span></span>−<span>12</span></span></span>
Hey there :)
( 5y + 9 )( 6y - 1 )
We need to use FOIL to expand, that is
First Terms
Outer Terms
Inner Terms
Last Terms
First Outer Inner Last
( 5y )( 6y ) + ( 5y )( - 1 ) + 9 ( 6y ) + 9 ( - 1 )
30y² - 5y + 54y - 9
Combine, if any, the like-terms
30y² + 49y - 9
