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Ahat [919]
3 years ago
7

Please help!! Find the value of x. 6 8 A D 4 x = [?] Enter

Mathematics
2 answers:
blondinia [14]3 years ago
7 0
The answer will be 5 ya welcome
dmitriy555 [2]3 years ago
7 0

Answer:

3

Step-by-step explanation:

By angle bisector property:

\frac{6}{x}  =  \frac{8}{4}  \\  \\  \frac{6}{x}  = 2 \\  \\ x =  \frac{6}{2}  \\  \\ x = 3

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den301095 [7]

there is 120 ways to get the word banana

4 0
4 years ago
A box contains 95 pink rubber bands and 90 brown rubber bands. You select a rubber band at random from the box. Find each probab
vivado [14]

Answer:A. The theoretical probability for pink is 95/185 or about 51.35%

B. The theoretical probability for brown is 90/185 or about 47.82%.

C. To find the experimental probability, we will make another fraction. The number of outcomes will be the numerator and the total will be the denominator.

Pink  36/69 = 52.17%

Brown  33/69 = 47.82%

Step-by-step explanation:

4 0
3 years ago
Joe is performing a dilation. One of his points is Y'(-4, 2), and another point is Y(-2, 1). What scale factor is he using?
IRINA_888 [86]
I would say c.-1/2 but I'm not certain
5 0
4 years ago
Read 2 more answers
Is 9.521521521 rational or irrational
enyata [817]

If the numbers after the decimal terminate, yes, it's rational.

9.521521521 = 9,521,521,521 / 1,000,000,000

If they don't terminate, but the pattern continues (which I suspect is the case here), yes, it's still rational.

If <em>x</em> = 9.521521521…, then

1000<em>x</em> = 9521.521521521…

Subtract <em>x</em> from this to eliminate the fractional part:

1000<em>x</em> - <em>x</em> = 9521.521521521… - 9.521521521…

999<em>x</em> = 9512

<em>x</em> = 9512/999

If they don't terminate, but the pattern does <em>not</em> continue, meaning the next few digits could be something random like

9.521521521<u>19484929271283583457</u>…

then the number would be irrational.

7 0
3 years ago
Factor the following quadratic equation; <br><img src="https://tex.z-dn.net/?f=12%20%7Bx%7D%5E%7B2%7D%20%20%2B%2022x%20-%2014" i
Bogdan [553]

Answer:

2(3x + 7)(2x - 1)

Step-by-step explanation:

You can see it a little easier if you take out a common factor of 2

2(6x^2 + 11x - 7)

The 6 leaves you with a lot of factors, the 7 does not. It only has 2 factors.

Let 6 factor into 2 and 3 and the 7 into 7 and 1

2(3x - 1 )(2x + 7)

Now remove the brackets.

2(6x^2 + 21x - 2x - 7) This obviously does not work but we'll combine like terms anyway.

2(6x^2 + 19x - 7)

So we'll try it again

2(3x + 7)(2x - 1)

2(6x^2 + 14x - 3x - 7)    Looks like we have it.

2(6x^2 + 11x - 7)

So the right factors are

2(3x + 7)(2x - 1)

5 0
4 years ago
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