Answer:
Step-by-step explanation:
The figure required in the question is missing, the figure can be found in attachment.
Transforming points T and V according to the rule (x,y) -> (3/4x, 3/4y), we get:
T(-4, 8) -> (-4*3/4, 8*3/4) -> (-3, 6) which corresponds to T'
V(0, 4) -> (0*3/4, 4*3/4) -> (0, 3) which corresponds to V'
The answer selected in the question is correct E. is the answer
Answer:
i think you multiply them or add them
Step-by-step explanation:
I believe the answer is C. third choice
<span>f(x) ≥ 0 over the interval [–1, 1].</span>
Answer:
The equation of the sphere in standard form is
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Step-by-step explanation:
<u>Step 1</u>:-
The equation of the sphere having center and radius is

Given centered of the sphere is (-6,10,5) and radius r=5

on simplification,we get


simplify , we get
