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3 years ago

Which of the following problems represents the following:

Mathematics

1 answer:

madam [21]3 years ago

5 0

Answer:

Step-by-step explanation:

"Turn around phrase" just means that you are subtracting the last number minus the first number. Subtracting the negative number is written as -(-34.7)

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Use the quadratic formula to solve x2 – 3x - 2 = 0.

r-ruslan [8.4K]

Answer:

x = 2 , 1

Step-by-step explanation:

6 0

3 years ago

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Please help me I'm super super stuck on my Math homework

leonid [27]

The answer is A or it should be

5 0

3 years ago

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3. Write the equation. Slope: riset Run y intercept: equation: y=mx+b;

larisa [96]

Answer: y = 1/4 x – 4

OR y = x/4 –4

m is the slope. b is the y-intercept.

Without numbers on the x and y axis, it may not be correct. But assuming a normal scale, the slope is positive 1/4 and the y-intercept is -4

Step-by-step explanation: To find the slope, m, determine "rise over run"

Look for places where the graphed line crosses the grid at intersections. There seems to be such places at (–4,–5), (0,–4) and (4,–3)

The "rise" is the difference in y-values. Here, they increase by 1.

The "run" is the difference in x-values. Here they increase by 4.

So the slope is 1/4. Put that in place of m.

The graphed line crosses the y-axis at –4

That is the y-intercept. Use -4 in the place of b

Keep the y and x; substitute the values for m and b we found.

y = 1/4 x – 4

y = x/4 – 4 This makes it clear that x is not in the denominator of the fraction, 1/4, and in calculations with given coordinates, the value of x will be divided by 4.

3 0

3 years ago

Compare and Contrast: Two equations are listed below. Solve each equation and compare the solutions. Choose the statement that i

Oksana_A [137]

Answer:

equation 2

Step-by-step explanation:

6 0

2 years ago

The pregnancy length in days for a population of new mothers can be approximated by a normal distribution with a mean of days an

solniwko [45]

Answer:

(a) 283 days

(b) 248 days

Step-by-step explanation:

The complete question is:

The pregnancy length in days for a population of new mothers can be approximated by a normal distribution with a mean of 268 days and a standard deviation of 12 days. (a) What is the minimum pregnancy length that can be in the top 11% of pregnancy lengths? (b) What is the maximum pregnancy length that can be in the bottom 5% of pregnancy lengths?

Solution:

The random variable X can be defined as the pregnancy length in days.

Then, from the provided information $X\sim N(\mu=268, \sigma^{2}=12^{2})$ .

(a)

The minimum pregnancy length that can be in the top 11% of pregnancy lengths implies that:

P (X > x) = 0.11

⇒ P (Z > z) = 0.11

⇒ z = 1.23

Compute the value of x as follows:

$z=\frac{x-\mu}{\sigma}\\\\1.23=\frac{x-268}{12}\\\\x=268+(12\times 1.23)\\\\x=282.76\\\\x\approx 283$

Thus, the minimum pregnancy length that can be in the top 11% of pregnancy lengths is 283 days.

(b)

The maximum pregnancy length that can be in the bottom 5% of pregnancy lengths implies that:

P (X < x) = 0.05

⇒ P (Z < z) = 0.05

⇒ z = -1.645

Compute the value of x as follows:

$z=\frac{x-\mu}{\sigma}\\\\-1.645=\frac{x-268}{12}\\\\x=268-(12\times 1.645)\\\\x=248.26\\\\x\approx 248$

Thus, the maximum pregnancy length that can be in the bottom 5% of pregnancy lengths is 248 days.

8 0

3 years ago