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3 years ago

Two cats, Fluffy and Fireball, met in the park. Fluffy's tail is 1/3, of a meter long. Fireball's tail is 1/4 of a meter long.

Mathematics

2 answers:

Lunna [17]3 years ago

6 0

1/3 - 1/4 = 4/12 - 3/12 = 1/12....Fluffy's tail is 1/12 meters longer then Fireball's tail

iren [92.7K]3 years ago

4 0

Answer:Fluffy's tail is $\frac{1}{12}$ meter longer than Fireball's.

Step-by-step explanation:

It is given Fluffy and Fireball tails are $\frac{1}{3} and \frac{1}{4}$ meters long.

We need to find how long is Fluffy's tail than Fireball's.

To find that we subtract the two fractions:

$\frac{1}{3} -\frac{1}{4}$

To subtract the fractions we first find the common denominator.The Least common multiple of 3 and 4 is 12.Writing equivalent fractions with denominator 12 we have:

$\frac{1}{3} -\frac{1}{4} =\frac{4}{12} -\frac{3}{12}$

Denominators same numerators can be subtracted:

$\frac{4-3}{12} =\frac{1}{12}$

Fluffy's tail is $\frac{1}{12}$ meter longer than Fireball's.

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Which of these expressions CANNOT be simplified by combining like terms?

densk [106]

$5ab^{3} +7-3a^{2} b ^{2} +a^{3}b+10$ can be simplified to by adding the 7 and 10 to get $a^{3}b-3a^{2} b ^{2}+ 5ab^{3} + 17$ .

$5ab^{3}+3a^{2}b^{2}+a^{3}b -10$ cannot be simplified any more by combining like terms.

By distributing the 2b into the parentheses, you can simplify the expression:
$5ab^{3}+2b(3ab^{2})+a^{3}b-10\\
5ab^{3}+6ab^{3}+a^{3}b-10\\
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Here you can just add:
$5a^{3}b^{3}+3a^{2}b^{2}+a^{3}b^{3}-10ab\\
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Thus, the only expression that cannot simplify any more using adding like terms is the second, $5ab^{3}+3a^{2}b^{2}+a^{3}b -10$ .

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3 years ago

Read 2 more answers

A shirt was marked down 25% which means you saved $15. What was the original cost of the shirt? What is the new price?

wlad13 [49]

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3 years ago

What is the sum of the first 51 consecutive odd positive integers?

Angelina_Jolie [31]

We call:

$a_{n}$ as the set of the first 51 consecutive odd positive integers, so:

 $a_{n} = \{1, 3, 5, 7, 9...\}$

Where:
$a_{1} = 1$
$a_{2} = 3$
$a_{3} = 5$
$a_{4} = 7$
$a_{5} = 9$
and so on.

In mathematics, a sequence of numbers, such that the difference between two consecutive terms is constant, is called Arithmetic Progression, so:

3-1 = 2
5-3 = 2
7-5 = 2
9-7 = 2 and so on.

Then, the common difference is 2, thus:

 $a_{n} = \{ a_{1} , a_{1} + d, a_{1} + d + d,..., a_{1} + (n-2)d+d\}$

Then:

 $a_{n} = a_{1} + (n-1)d$

So, we need to find the sum of the members of the finite series, which is called arithmetic series:

There is a formula for arithmetic series, namely:

 $S_{k} = ( \frac{a_{1} + a_{k}}{2} ).k$

Therefore, we need to find:
 $a_{k} = a_{51}$

Given that $a_{1} = 1$ , then:

$a_{n} = a_{1} + (n-1)d = 1 + (n-1)(2) = 2n-1$

Thus:
$a_{k} = a_{51} = 2(51)-1 = 101$

Lastly:

$S_{51} = ( \frac{1 + 101}{2} ).51 = 2601$

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3 years ago

Help please!!

Savatey [412]

Answer:

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Step-by-step explanation:

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3 years ago

3/5 of of Garys fish are guppies. 1/6 of them are red. what fraction of guppies are red?

Anvisha [2.4K]

Answer:

The fraction of red guppies = 1/10

Step-by-step explanation:

Garys fish are guppies = 3/5

1/6 of them are red.

Number of red guppies = ?

To find the fraction of red guppies, we will multiply both the fractions.

Number of red guppies = 3/5 * 1/6

Number of red guppies = 3/30

Number of red guppies = 1/10

Thus the fraction of red guppies = 1/10 ....

7 0

3 years ago

Two cats, Fluffy and Fireball, met in the park. Fluffy's tail is 1/3​​, of a meter long. Fireball's tail is 1/4 of a meter long.

Two cats, Fluffy and Fireball, met in the park. Fluffy's tail is 1/3, of a meter long. Fireball's tail is 1/4 of a meter long.