Answer:
Step-by-step explanation:
Given equation is,
x² + (p + 1)x = 5 - 2p
x² + (p + 1)x - (5 - 2p) = 0
x² + (p + 1)x + (2p - 5) = 0
Properties for the roots of a quadratic equation,
1). Quadratic equation will have two real roots, discriminant will be greater than zero. [(b² - 4ac) > 0]
2). If the equation has exactly one root, discriminant will be zero [(b² - 4ac) = 0]
3). If equation has imaginary roots, discriminant will be less than zero [(b² - 4ac) < 0].
Discriminant of the given equation = 
For real roots,

p² + 2p + 1 - 8p + 20 > 0
p² - 6p + 21 > 0
For all real values of 'p', given equation will be greater than zero.
Answer:
(1, 3)
Step-by-step explanation:
The first endpoint (the one on the left) is (-3, 2). The second endpoint (the one on the right) is (5, 4). To find the midpoint, find the middle of both x and y. To do that, add the values of x and y respectively and divide by 2:
for x-value of midpoint:
(x-value of first endpoint + x-value of second endpoint) / 2
= (-3 + 5) / 2
= 2 / 2
= 1
for y-value of midpoint
(y-value of first endpoint + y-value of second endpoint) / 2
= (2 + 4) / 2
= 6 / 2
= 3
Answer:
split the figure into two parts
1st part is 7 × (12-3)
2nd part is 3×4
(9×7) + (3×4)