5) all you have to do is calculate which would be 2.9166...
6) 65.898
The total amount of angles in quadrilateral is 360.so:
z=360-(122+79+90)
z=360-291
z=69
3x+5x-12=180
8x=180+12
8x=192
x=192/8
x=24
angle 1 = 5x-12
=5(24)-12
=120-12
=108
angle 2= 3x =3*24=72
angle 1 = angle 9
angle 9= 108
Answer:
151.9 if the side length of the pentagon/ base of each triangle is 6 m
Step-by-step explanation:
if the side length of the pentagon/ base of each triangle is 6 m then it is a pretty simple question, we just need to add the surface area of the base pentagon and each triangle.
We have the area of the base, so we just need the triangles. The area of a triangle is .5bh, where the base of a triangle here is one side of the pentagon and the height is that indicated red 6. so that means one triangle has an area of .5*6*6 or 18. There are 5 triangles total so that means that with all the triangles there is an area of 90. Adding that to 61.9 gets us 151.9. let me know if you need any more help.
You want the (positive) distance when the height is 0, 0= -d^2 + 10d +5.
You would factor that out(You'd get radicals), and the final answer would be
<span>5±<span>30<span>−−</span>√</span></span><span>
You'd take the only positive one of the two, 5 + srt(30)
I hope I did that right :/</span>
