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2 years ago

Which amount is greater 8/16 or 9/12

Mathematics

1 answer:

Marysya12 [62]2 years ago

8 0

Answer:

8/16 < 9/12

Step-by-step explanation:

Because the LCD is 48

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A documentary is a film that

DanielleElmas [232]

Answer:

1. the answer is nonfictional story about a person, topic, or event

Step-by-step explanation:

hope this helps

3 0

2 years ago

In 2010, the population of Kingsford was 8000. By 2014 the population had increased by 15% and 2/5 of the population was age 12

Anastasy [175]

<h2>Hello!</h2>

The answer is: The population age 12 or under was 3680.

If in 2010 the population of Kignsford was 8000, and by 2014 the population had increased by 15% we need to calculate the total population and then, calculate how many people was age 12 or under.

We must remember that we cannot work with percentage values, so, to make 15% a real number, we need to divide it by 100:

$15(Percentage)=\frac{15}{100}=0.15$

So,

Calculating the population by 2014, we have:

$Population_{2014}=Population_{2010}+ Population_{2010}*0.15$

Then, substituting we have:

$Population_{2014}=8000+ 8000*0.15=9200$

Now, calculating the population that was age 12 or under, knowing that it was 2/5 of the total population, we have:

$Population=TotalPopulation*\frac{2}{5}\\\\Population=9200*\frac{2}{5}=3680$

So, the population age 12 or under was 3680.

Have a nice day!

6 0

3 years ago

Suppose that surface σ is parameterized by r(u,v)=⟨ucos(3v),usin(3v),v⟩, 0≤u≤7 and 0≤v≤2π3 and f(x,y,z)=x2+y2+z2. Set up the sur

Bad White [126]

Looks like you have most of the details already, but you're missing one crucial piece.

$\sigma$ is parameterized by

$\vec r(u,v)=\langle u\cos3v,u\sin3v,v\rangle$

for $0\le u\le7$ and $0\le v\le\frac{2\pi}3$ , and a normal vector to this surface is

$\dfrac{\partial\vec r}{\partial u}\times\dfrac{\partial\vec r}{\partial v}=\left\langle\sin3v,-\cos3v,3u\right\rangle$

with norm

$\left\|\dfrac{\partial\vec r}{\partial u}\times\dfrac{\partial\vec r}{\partial v}\right\|=\sqrt{\sin^23v+(-\cos3v)^2+(3u)^2}=\sqrt{9u^2+1}$

So the integral of $f(x,y,z)=x^2+y^2+z^2$ is

$\displaystyle\iint_\sigma f(x,y,z)\,\mathrm dA=\boxed{\int_0^{2\pi/3}\int_0^7(u^2+v^2)\sqrt{9u^2+1}\,\mathrm du\,\mathrm dv}$

6 0

3 years ago

What is 6x3/7 as a mixed number?

Anastaziya [24]

<span>6x3/7
6 x 3=18\7
answer=2 4\7</span>

6 0

3 years ago

(a) Find an angle between 0 and 2π that is coterminal with −19π10.

Katarina [22]

Answer:

$\dfrac{\pi}{10}$ .

Step-by-step explanation:

All coterminal angles of an angle $\theta$ are defined as

$\theta +2n\pi$ or $\theta + n360^{\circ}$

where, n is an integer.

The given angle is

$\theta=-\dfrac{19\pi}{10}$

So, all coterminal angles of an angle $\theta$ are

$-\dfrac{19\pi}{10}+2n\pi$

For n=1,

$\Rightarrow -\dfrac{19\pi}{10}+2(1)\pi$

$\Rightarrow -\dfrac{19\pi}{10}+2\pi$

$\Rightarrow \dfrac{-19\pi+20\pi}{10}$

$\Rightarrow \dfrac{1\pi}{10}$

Since, $\dfrac{\pi}{10}$ between 0 and 2π, therefore, the required coterminal angle is $\dfrac{\pi}{10}$ .

6 0

3 years ago